4598x10 2 2 79500250 318 320 32x10 2 70 10 3 80 10 4 007 0008 0062

# 4598x10 2 2 79500250 318 320 32x10 2 70 10 3 80 10 4

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=1.4598x10279,500 ÷ (2.5 × 102)=79,500/250=318=320=3.2x102(7.0 × 10–3) – (8.0 × 10–4)=.007-.0008=.0062=6.2x10-3(1.0 × 104) × (9.9 × 106)=9.9x1010(Reference: Chang 1.31) 4. What is the number of significant figures in each of the following measurements? (8 points)5.Express the results in the proper number of significant figures. (12 points)a.4867 mi=4b.56 mL=2c.60,104 ton=5d.2900 g=4e.40.2 g/cm3=3f.0.0000003 cm=1g.0.7 min=1h.4.6 × 1019atoms=2(Reference: Chang 1.33)(Reference: Chang 1.35) 6.Carry out the following conversions: (16 points) 2Copyright © 2016 by Thomas Edison State University. All rights reserved. (Reference: Chang 1.39)7.The average speed of helium at 25°C is 1255 m/s. Convert this speed to miles per hour (mph). (4 points)(Reference: Chang 1.41)1 mile = 1609 m1609m – 1 mile1255 m = 1 mile/1609m x 1255m1255m = .779 mile3600 sex = 1 hour1 sex = 1 hr/3600 sec x 1 sec1 sec = 2.77x10-4hrSpeed in mile/hr = .779mile/2.77x10-4hr= 2807.355 mph3Copyright © 2016 by Thomas Edison State University. All rights reserved.  #### You've reached the end of your free preview.

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• Summer '14
• Chemistry, Kilogram, Litre, Chemical substance, Chemical compound, Thomas Edison State College
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