# Tire circumference 2 16 π 100531 totaldistrance

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tire circumference=216π ≈100.531¿ Totaldistrance travelled=100.53139615.756 1760312 62.857miles Terry was travelling around 7.857mph above the speed limit, so he deserves a ticket. 110.Find the area of sector: Area=1 2 r2 θ ; r = 8 s=4π=8θ θ=4π8= π 2
Area=1282 π2=32π 2 =16π Section 6.2 32.Find a calculator approximation for: sec(8.3429)=1 cos(8.3429) 2.129 58.Find the value of s in the interval[0, π 2 ] that makes the following statement true: cots=0.2994 s tan¿=0.2994 ¿ s=1/¿ cot¿ tans= 1 0.2994 s=tan1 (1 0.2994 ) 1.280 88.Use the formulaω= θ t to find the value of the missing variable: ω=4.316radians per min;t=4.752min 4.316= θ 4.752
θ=4.3164.75220.510 90.Use the formulav=to find the value of the missing variable: r=8cm;ω=9π 5 radian per sec v=89π 5 45.239 Section 6.3 20.Graph the function over the interval [-2π, 2π]. Give the amplitude. y=−3cosx According to the amplitude statement on P.572, amplitude of this function is 3. x=0,y=−3 ; x=2π , y=−3 ; x=−2π , y=−3
48.a. Find the systolic and diastolic pressures: Referring to the graph on P.580: Systolic pressure: 120 mm mercury Diastolic pressure: 80 mm mercury b. Find the amplitude of the graph Amplitude=12080 2 =20mmmercury c. Find the pulse rate (the number of pulse beats in 1 min) for this person: Period = 0.8s Pulse Rate = 60/0.8 = 75 beats per minute 56. E=5cos 12πt ;t=time measuredseconds a. Find the amplitude and the period. According to the amplitude statement on P.572, amplitude is 5. Period=2π12π=1 6 0.167 Refer to P.573 b. Find the Frequency: Frequency = 1/0.167 = 5.99Hz c. Find E when t=0.02, 0.04, 0.08, 0.12, 0.14 t0.020.040.080.120.14 E = 5 cos 12πt3.6450.314-4.961-0.9372.679 Wrong problem(-2.5) Section 6.4
2. y=sin(x+ π 4 ) Using the horizontal translation method, the graph will bey=sinx left shifted π/4 units. Since sin 0 = 0, Graph G is the match for this equation. 16. y=2sin(3x4 ) 03x42π 43x≤2π+4 43≤x ≤ 2π+4 3 Statement D is the appropriate description since amplitude is 2, phase shift is 4/3 and period is 2π/3.

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