How did you determine this value 2 pt if rochester is

Info iconThis preview shows pages 2–3. Sign up to view the full content.

View Full Document Right Arrow Icon
How did you determine this value? (2 pt) If Rochester is going to have the same proportion, I would expect there to be about 17 schools making AYP. I determined this by multiplying 35 (the number of schools in the Rochester district) by .49 (the percentage we’re comparing Rochester’s to). c. Consider the following outcomes from 1000 simulations from Tinkerplots.
Background image of page 2

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
The appropriate probability value (or p-value) from these 1000 simulations for our research  question is the number of outcomes less than or equal to 15 out of 1000, which is  (100+96+61+24+16+4) / 1000 = 301 / 1000 = 0.301.  Does this p-value provide enough  statistical evidence to support our research question?  Explain. (3 pts) No, the acceptable p-value is less than .05 or 5%. .301 or 30% is too high for the statistical evidence to be seen as supported. 4. There are a lot of different demographic variables that influence whether or not a school can achieve the standard of Making AYP. For example, a school with a disproportionate number of students on a free/reduced lunch program tends to have more trouble making AYP. For reasons such as this, suppose that the proportion of urban schools that typically make AYP status in any given year is about
Background image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page2 / 3

How did you determine this value 2 pt If Rochester is going...

This preview shows document pages 2 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online