Put your answers above each symbol in the equation

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Write the oxidation number for each atom in the following equation. Put your answers above each symbol in the equation. Identify which substance is oxidized, which is reduced, the oxidizing agent, and the reducing agent. (8 points) +6 –2 –1 +1 +3 0 +1 –2 Cr 2 O 7 2− ( aq ) + 6Cl ( aq ) + 14H + ( aq ) 2Cr 3+ ( aq ) + 3Cl 2 ( g ) + 7H 2 O( l ) Cl in Cl is oxidized Cr in Cr 2 O 7 2− is reduced Cl is the reducing agent Cr 2 O 7 2− is the oxidizing agent.
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