Multiply equation 1 by 002 and then subtract equation 2 from it and solve for y

Multiply equation 1 by 002 and then subtract equation

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Multiply equation 1 by 0.02 and then subtract equation 2 from it and solve for y , 0.02 3200 0.02 0.02 0.02 0.02 64 x y z x y z Therefore, 0.02 0.02 0.02 64 0.02 0.03 0.06 160 0.01 0.04 96 x y z x y z y z   Do not forget to change the sign of below equation. Then, 0.01 0.04 96 0.01 0.04 96 0.01 0.04 96 0.01 96 0.04 96 0.04 0.01 y z y z y z y z z y    
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Put the value of y as 96 0.04 0.01 z in third equation and solve for z , 1900 96 0.04 1900 0.01 96 0.04 0.01 19 96 0.04 0.01 19 96 0.05 19 0.05 19 96 0.05 115 115 0.05 2300 y z z z z z z z z z z z z Put the value of z as 2300 back in equation 3 to get y , 1900 2300 1900 1900 2300 y z y y y   400 400 y Now put the value of y and z in first equation to get x , 3200 400 2300 3200 3200 400 2300 500 x y z x x x Hence, the total amount invested at rate 2%, 3% and 6% is 500,400 and 2300 To check the answer, put the values of x , y and z in any equation, 3200 500 400 2300 3200 3200 3200 x y z
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Solution verified. </ EXPLANATION>
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