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Feedback Correct. From the information provided, we can determine William’s and Linda’s genotypes. William is hemophilic and must be XhY. Linda, a carrier, is heterozygous, so she must be XHXh. Crossing XhY and XHXh results in 50% of sons that are XHY and do not have the condition, and 50% that are XhY and do have the condition. Human Inheritance Quiz ...
Points: 10 out of 10 Question 5 Sickle cell anemia is an autosomal recessive disorder. If two heterozygous individuals breed, what is the chance that their offspring will develop Sickle cell anemia?
Points: 0 out of 10 Question 6 Sickle cell anemia is an autosomal recessive disorder. A person with the disorder and a person that is a carrier mate. ( A carrier has the allele for the trait but does not express it .) What is the chance that their offspring will develop sickle cell anemia?
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Points: 10 out of 10 Question 4 If William and Linda have a daughter, what is the probability that she will have this condition?

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