The number of fundamental electric charges on the oil

Info icon This preview shows pages 48–49. Sign up to view the full content.

View Full Document Right Arrow Icon
The number of fundamental electric charges on the oil drop is 18 19 2.40 10 C 15 1.60 10 C q e × = = ×
Image of page 48

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
38.49. Model: Assume the classical electric force is the centripetal force. 2 2 2 e 2 e Ke v Ke F m v r r m r = = = Visualize: We are given 600 nm. λ = We also know that for electromagnetic waves . c f λ = Solve: (a) The speed is the circumference of the orbit divided by the period. 2 2 r v rf T π π = = 2 e 2 2 2 Ke m r v v r f c c λ λ π π π = = = Square both sides. 2 e 2 2 2 2 4 Ke m r r c λ π = Multiply both sides by . r 2 2 3 2 2 e 4 Ke r c m λ π = Take cube roots. 10 2 2 3 2 2 9 2 2 19 2 9 2 3 2 8 2 31 4 (8 99 10 N m C )(1 60 10 C) (600 10 m) 4 (3 00 10 m s) (9 11 10 kg) 2 95 10 m 0 295 nm e Ke r c m λ π π = . × / . × × = . × / . × = . × = . (b) The total mechanical energy of the classical atom was found in Problem 38.47. 19 2 2 19 12 2 2 10 0 (1 60 10 C) 3 90 10 J 2 44eV 8 8 (8 85 10 C N m )(2 95 10 m) e E r πε π . × = − = − = − . × = − . . × / . × Assess: While we don’t expect the classical analysis to be perfect, the result is in a reasonable range.
Image of page 49
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern