Present state next state sr inputs d inputs jk inputs

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Present State Next State SR inputs D inputs JK inputs T inputs x A B A + B + S A R A S B R B D A D B J A K A J B K B T A T B 0 0 0 0 1 0 0 1 1 0 0 1 0 1 1 0 1 1 0 0 1 0 0 0 1 1 0 1 1 1 1 1 0 0 0 1 1 1 1 0 Remember, the darker columns show the state transition and excitation information for flip-flop A, and the lighter columns show the same information for flip-flop B. The table is filled using the same excitation information as was used in the previous example. Here is that excitation information summarized: Q Q + S R D J K T 0 0 0 × 0 0 × 0 0 1 1 0 1 1 × 1 1 0 0 1 0 × 1 1 1 1 × 0 1 × 0 0 Based on this information, the correct excitation information can be inserted into the table for the proper set of transitions. (A A + , B B + ) Here is the state table filled in with that information: Present State Next State SR inputs D inputs JK inputs T inputs x A B A + B + S A R A S B R B D A D B J A K A J B K B T A T B 0 0 0 0 1 0 × 1 0 0 1 0 × 1 × 0 1 0 0 1 1 0 1 0 0 1 1 0 1 × × 1 1 1 0 1 0 1 1 × 0 1 0 1 1 × 0 1 × 0 1 0 1 1 0 0 0 1 0 1 0 0 × 1 × 1 1 1 1 0 0 0 1 0 × 1 0 0 1 0 × 1 × 0 1 1 0 1 1 1 1 0 × 0 1 1 1 × × 0 1 0 1 1 0 0 0 0 1 0 × 0 0 × 1 0 × 1 0 1 1 1 1 0 × 0 0 1 1 0 × 0 × 1 0 1
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Step 4: Obtain the logic equations. With the excitation information complete, each input must now be mapped, so that a set of logic equation can be determined. With the exception of needing 3-variable Karnaugh maps instead of the 2-variable maps of the previous example, the process of obtaining the logic equations is the same as in the first example. Here are the maps for each set of equations.
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  • Summer '06
  • JSThweatt
  • present state, State A+ B+

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