A yes b no 3 is it possible for an object to have a

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A - Yes B - No 3) Is it possible for an object to have a positive velocity at the same time as it has a negative acceleration? A - Yes B - No
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1/5/11 MORE 1-D KINEMATICS -We saw that v = dx / dt -In “calculus” language we would write dx = v dt, which we can integrate to obtain: -Graphically, this is adding up lots of small rectangles:
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1/5/11 1D MOTION WITH CONSTANT ACCELERATION - Calculu s: -Also recall that -Since a is constant, we can integrate this using the above rule to find: -Similarly, since we can integrate again to get:
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1/5/11 EQUATIONS FOR CONSTANT ACCELERATION Positio n: Velocit y: Accelerati on:
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1/5/11 SKATEBOARDER A skateboarder coasts down a long hill, starting from rest and moving with constant acceleration to cover a certain distance in 6 s. In a second trial, he starts from rest and moves with the same acceleration for only 2 s. How is his displacement different in this second trial compared with the first trial? A: one-third as large B: three times larger C: one-ninth as large D: nine times larger E: 1/√3 times as large F: √3 times larger
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1/5/11 SPEED -Velocity is positive or negative. -Speed is always positive: Magnitude of the velocity vector. -In 1D speed is the absolute value of the velocity: |v|
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1/5/11 PROBLEM 2.11 -A particle starts from rest and accelerates as shown in the figure. - Determine : (a) the particles speed at t=10 s and t=20s (b) the distance traveled in the first 20 s
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1/5/11 USEFUL FORMULA -Solving for t: *Eliminatin g t: *Simplifying :
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1/5/11 ANOTHER USEFUL FORMULA -Solving for a: *Eliminatin g a: *Simplifying :
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1/5/11 CHAPTER 2.2 NOTES Physics 195 Lecture (part two)
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1/5/11 MOTION WITH CONSTANT ACCELERATION (review) Basic equations: From which we derived:
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1/5/11 SKYDIVER JUMPS OUT A skydiver is falling straight down, along the negative y direction. During the initial part of the fall, her speed increases from 16 to 28 m/s in 1.5 s.
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