Simone Garcia CHE 111 General Chemistry I Lab Moles of 13 formed 3 mol of KIO3

Simone garcia che 111 general chemistry i lab moles

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Simone Garcia CHE 111: General Chemistry I Lab Moles of 13 - formed = 3* ( mol of KIO3) = 3* (mol of KIO3) = 3 * 1.705 m/mol = 5.115m/mol Moles of C6H8O6 = 5.115m/mol Mass of vitamin C = mol of vitamin C * molecular weight vitamin C = 5.115 m/mol * 176.12g/mol = 900.8538mg = 900.9mg Group 3 Mass of KIO3 =.235g Moles of KIO3 =.235g/214 g ( molecular weight of KIO3) = .00110 moles Concentration of KIO3 solution: .00110 moles/ .1 L = .01 mol/L KIO3 reacted = (91.7mL)* (.01 mol/L) = 0.917 m/mol Moles of 13- formed = 3 * (mol of KIO3)= 3 *.917m/mol - 2.75 m/mol Moles of C6H8O6 = 2.75 m/mol Mass of vitamin C = mol of vitamin C * molecular weight vitamin C = 2.75 m/mol * 176.12g/mol = 484.506 mg = 485 mg Average Vitamin C mass - (485 + 900.9 +755.9)/3 = 714 mg Standard deviation = Relative standard deviation: (211.1 / 714) * 100 = 29.6 Results and Discussion During this experiment each group used different amounts of KIO3 and some groups used the back of the vitamin tablet bottle to determine the mass of the Vitamin C and and others actual measured the crushed tablet. That is the reason why some peoples titration reactions occurs faster than others. Group 1 calculation were mass of KIO3 = .231g, moles of KIO3 = . 231g / 214g (molecular weight of KIO3) = .00108 moles concentration of KIO3 solution .00108 moles/ .1 L = .0108 mol/L . KIO3 reacted =(132.5mL) * (.00108 mol/L) = 1.431m/mol, moles of Page 4 of 6
Simone Garcia CHE 111: General Chemistry I Lab 13- formed = 3* ( molof KIO3) = 3* 1.431m/mol = 4.293m/mol, moles of C6H8O6 = 4.293m/mol. Mass of vitamin C = mol of vitamin C * molecular weight vitamin C = 4.293 m/mol * 176.12g/mol =755.907mg = 755.9mg. Group 2 calculations were mass of KIO3 =.214g, mole of KIO3 =.214/ 214 g ( molecular weight of KIO3) =.001 moles ,concentration of KIO3 Solution : .001 moles / .1 L = .01 mol/L. KIO3 reacted = (170.5 mL)*(.01 mol/L) = 1.705m/mol, moles of 13 - formed = 3* ( mol of KIO3) = 3* (mol of KIO3) = 3 * 1.705 m/mol = 5.115m/mol ,moles of C6H8O6 = 5.115m/mol. Mass of vitamin C = mol of vitamin C * molecular weight vitamin C = 5.115 m/mol * 176.12g/mol = 900.8538mg = 900.9mg. Group 3 mass of KIO3 =.235g, moles of KIO3 =.235g/214 g ( molecular weight of KIO3) = .00110 moles, concentration of KIO3 solution: .00110 moles/ .1 L = .01 mol/L. KIO3 reacted = (91.7mL)* (.01 mol/L) = 0.917 m/mol, moles of 13- formed = 3 * (mol of KIO3)= 3 *.917m/mol - 2.75 m/mol, moles of C6H8O6 = 2.75 m/mol. Mass of vitamin C = mol of vitamin C * molecular weight vitamin C = 2.75 m/mol * 176.12g/mol = 484.506 mg = 485 mg. The average mass of vitamin C was (485 + 900.9 +755.9)/3 = 714 mg. Standard deviation

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