Then p 1a p 1a 12 2 p 1a 9331 psfa 24 determining the

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then P 1a P 1a 12 2 := P 1a 9331 = psfa 2.4 Determining the pressure in the water pipe at A. Express the pressure in psia. 1 2 3 A 30 in. 20 in. 5 ft. OIL SG = 0.8 WATER MERCURY SG = 13.6 20 ft. 50 psig P atm = 14.8 psia P atm 14.8 := psia By definition SG ρ ρ water = As recommended in lectures, when working in british units begin by converting all masses from lb m to slugs: By definition slug lb m 32.174 = For water ρ w 62.4 := lb m /ft 3 (given) then ρ w ρ w 32.174 := ρ w 1.939 = slug/ft 3 and for oil SG oil 0.8 := ρ oil SG oil ρ w := 1 MAAE2300/2.4
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