Since V 250000 when t 0 and V 10000 when t 10 the line passes through the

# Since v 250000 when t 0 and v 10000 when t 10 the

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SinceV250,000 whent0 andV10,000 whent10, the line passes through the points0250000and1010000. The slope of the line through these points isgiven bym10,000250,000100 240,00010 24,000.Using the point-slope form of an equation of a line with theb.c.In 2014,t4 andV 24,0004250,000154,000, or \$154,000.d.The rate of depreciation is given bym, or \$24,000yr.050,000100,000150,000200,000250,00024681012tV(10, 10000)point1010000, we haveV10,000 24,000t10, orV 24,000t250,000. 23.Let the value of the workcenter system aftertyears beV. Whent0,V60,000 and whent4,V12,000. c.010,00020,00030,00040,00050,00060,000123456tV24.The slope of the line passing through the points0CandNSismSCN0SCN CSN. Using thepoint-slope form of an equation of a line with the point0C, we haveVC CSNt, orVCCSNt.25.The formula given in Exercise 24 isVCCSNt. WhenC1,000,000,N50, andS0, we haveV1,000,0001,000,000050t, orV1,000,00020,000t. In 2013,t5 andV1,000,00020,0005900,000, or \$900,000. In 2018,t10 andV1,000,00020,00010800,000,or \$800,000.26.The formula given in Exercise 24 isVCCSNt. WhenC24,000,N5, andS0, we haveV24,00024,00005t24,0004800t. Whent3,V24,000480039600, or \$9600.27. a.DSSa17. If we think ofDas having the formDSmSb, thenma17,b0, andDis a linearfunction ofS.b.D045000417117647, or approximately 11765 mg.28. a.Dtt124aa24ta24. If we think ofDas having the formDtmtb, thenma24,ba24, andDis a linear function oft.b.Ifa500 andt4,D44124500104167, or approximately 1042 mg.Full file at
221STRAIGHT LINES AND LINEAR FUNCTIONS29. a.The graph offpasses through the pointsP10175andP210103. Its slope is103175100 072.An equation of the line isy175 072t0ory 072t175, so the linear function isft 072t175.b.The percentage of high school students who drink and drive at the beginning of 2014 is projected to bef13 07213175814, or 814%.

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