S13Phys2BaLec27A

# At point c in the diagram from our previous attempt

• Notes
• 25

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At point c in the diagram: From our previous attempt (with loop rule):

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Kirchhoff’s Rules Now we have a relationship between all of the currents in the circuit. You can then: Apply another Kirchhoff’s Loop Rule to solve for I 3 . or try equivalent resistance to solve for I 3 . In either case, solving for the current through either resistor or the power dissipated through either resistor becomes rather simple after that. You will find that becoming skilled in BOTH equivalent resistance and Kirchhoff’s Rules will make solving circuit problems much easier.
Conservation of energy (per charge) 0 = 0 loop ( V ) Loop rule

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Junction rule = I in I out Conservation of charge (flow)
Clicker Question 27A-2 Initially light bulbs A and B are hooked up in series and connected to a voltage source. If the switch is closed, light bulb C will become hooked up in parallel with light bulb B. What happens to the brightness of light bulbs A and B when the switch is closed? All light bulbs have the same resistance in this circuit. A) Bulb A remains the same and Bulb B gets dimmer. B) Bulb A remains the same and Bulb B remains the same. C) Bulb A gets brighter and Bulb B gets dimmer. D) Bulb A gets dimmer and Bulb B gets dimmer.

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For Next Time (FNT) Finish reading Chapter 27 Finish working on the homework for Chapter 26
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• Spring '08
• schuller
• Physics, Resistor, Series and parallel circuits, loop rule, Kirchhoff’s Junction

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