Tros introductory chemistry preparing a 100 m nacl

This preview shows page 48 - 60 out of 116 pages.

Tro's Introductory Chemistry, Chapter 13 48 Preparing a 1.00 M NaCl Solution Weigh out 1 mole (58.45 g) of NaCl and add it to a 1.00 L volumetric flask. Step 1 Step 2 Add water to dissolve the NaCl, then add water to the mark. Step 3 Swirl to Mix
Image of page 48
Example 13.3: Calculating Molarity
Image of page 49
Tro's Introductory Chemistry, Chapter 13 50 Example: Calculate the molarity of a solution made by putting 15.5 g of NaCl into a beaker and adding water to make 1.50 L of NaCl solution.
Image of page 50
Tro's Introductory Chemistry, Chapter 13 51 Example: Calculate the molarity of a solution made by putting 15.5 g of NaCl into a beaker and adding water to make 1.50 L of NaCl solution. Write down the given quantity and its units. Given: 15.5 g NaCl 1.50 L solution
Image of page 51
Tro's Introductory Chemistry, Chapter 13 52 Write down the quantity to find and/or its units. Find: molarity (M) Information Given: 15.5 g NaCl; 1.50 L sol’n Example: Calculate the molarity of a solution made by putting 15.5 g of NaCl into a beaker and adding water to make 1.50 L of NaCl solution.
Image of page 52
Tro's Introductory Chemistry, Chapter 13 53 Collect Needed Equations and Conversion Factors: Molar Mass NaCl = 58.44 g/mol 58.44 g NaCl = 1 mol Information Given: 15.5 g NaCl; 1.50 L sol’n Find: molarity, M Example: Calculate the molarity of a solution made by putting 15.5 g of NaCl into a beaker and adding water to make 1.50 L of NaCl solution. solution liters solute moles Molarity =
Image of page 53
54 Design a Solution Map: Volume Solution Mass Solute Molarity Information Given: 15.5 g NaCl; 1.50 L sol’n Find: molarity, M CF: 58.44 g = 1 mol NaCl; Example: Calculate the molarity of a solution made by putting 15.5 g of NaCl into a beaker and adding water to make 1.50 L of NaCl solution. solution liters solute moles Molarity = L Solution Mole Solute liters moles M = NaCl g 58.44 moles 1 already liters
Image of page 54
Tro's Introductory Chemistry, Chapter 13 55 NaCl mol 2 5 0.26 g 58.44 NaCl mol 1 NaCl g 15.5 = × Apply the Solution Map Information Given: 15.5 g NaCl; 1.50 L sol’n Find: molarity, M CF: 58.44 g = 1 mol NaCl; Example: Calculate the molarity of a solution made by putting 15.5 g of NaCl into a beaker and adding water to make 1.50 L of NaCl solution. solution liters solute moles Molarity = solution L 1.50 NaCl mol 2 5 26 . 0 solution liters solute moles Molarity = = = 0.177 M NaCl
Image of page 55
56 Check the Solution The units of the answer, M, are correct. The magnitude of the answer makes sense since the mass of solute is less than the 1 mole and the volume is more than 1 L. molarity of solution = 0.177 M Information Given: 15.5 g NaCl; 1.50 L sol’n Find: molarity, M CF: 58.44 g = 1 mol NaCl; Example: Calculate the molarity of a solution made by putting 15.5 g of NaCl into a beaker and adding water to make 1.50 L of NaCl solution. solution liters solute moles Molarity =
Image of page 56
Example 13.4: Using Molarity in Calculations
Image of page 57
Tro's Introductory Chemistry, Chapter 13 58 Example: How many liters of a 0.114 M NaOH solution contains 1.24 mol of NaOH?
Image of page 58
Tro's Introductory Chemistry, Chapter 13 59 Example: How many liters of a 0.114 M NaOH solution contains 1.24 mol of NaOH?
Image of page 59

Want to read all 116 pages?

Image of page 60

Want to read all 116 pages?

You've reached the end of your free preview.

Want to read all 116 pages?

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern