Unit Five Self-Assessment Questions.docx

A moo 2 h 2 o h 2 moo 3 b moo 2 4 h 2 mo 2 h 2 o c 2

Info icon This preview shows pages 5–7. Sign up to view the full content.

a. MoO 2 + H 2 O H 2 MoO 3 b. MoO 2 + 4 H 2 Mo + 2 H 2 O c. 2 MoO 2 + O 2 2 MoO 3 d. MoO 2 + 4 H + Mo 4+ + 2 H 2 O 5) According to the following equation, Cl 2 is 3 Cl 2 + 2 Al 2 AlCl 3 a. Both oxidized and reduced b. Neither oxidized nor reduced c. Oxidized only d. Reduced only 6) According to the following partial equation, manganese Mn Mn 2+ + 2 e - a. Gains electrons and is oxidized b. Gains electrons and is reduced c. Loses electrons and is oxidized d. Loses electrons and is reduced 7) When an element is oxidized, its oxidation number a. Decreases, as electrons are gained b. Decreases, as electrons are lost c. Increases, as electrons are gained d. Increases, as electrons are lost 8) What are the oxidation numbers of sodium and oxygen atoms in Na 2 O, respectively? a. 0, 0 b. +1, +1 c. +1, -2 d. +1, -1 9) What is the oxidation number of manganese in KMnO 4 ? a. +7 b. +8 c. +1 d. +6 10) Which of the following statements is correct in regards to assigning oxidation numbers? a. Alkali metals can have an oxidation number of either 1+ or -1 b. Halogens can never have an oxidation number of -1 c. Oxygen must always have an oxidation number of -2, even in elemental form d. The oxidation number of alkaline earth metals in ionic compounds is always +2 11) What is the charge of the PO 4 n- ion, in which phosphorus has the oxidation number of +5 and each of the oxygen atoms has the oxidation number of -2? a. 0 b. 1- c. 2- d. 3- Section Two 1) A reducing agent a. Gains electrons b. Gains protons c. Loses electrons d. Loses protons 2) When a compound gains two electrons, it is
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

Unit Five Test on March 31, 2017 a. An oxidizing agent b. A reducing agent c. Oxidized d. A double-reducing agent 3) If an oxidation number of an atom in a compound increases from 2+ to 4+, the compound a. Is a reducing agent b. Is an oxidizing agent c. Gains electrons d. Gains protons 4) Which substance is the oxidizing agent in the following reaction? Cu (s) + 2 Ag + (aq) Cu 2+ (aq) + 2 Ag (s) a. Ag b. Ag + c. Cu d. Cu 2+ 5) In the following reaction, the reducing agent is Al (s) + Cr 3+ (aq) Al 3+ (aq) + Cr (s) a. Al (s) b. Al 3+ (aq) c. Cr 3+ (aq) d. Cr (s) 6) What is the oxidizing agent in the following reaction? Zn (s) + 2 Tl + (aq) Zn 2+ (aq) + 2 Tl (s) a. Tl (s) b. Tl + (aq) c. Zn (s) d. Zn 2+ (aq) 7) What is the reducing agent in the following reaction? 12 H + (aq) + 2 IO 3 - (aq) + 10 Fe 2+ (aq) 10 Fe 3+ (aq) + I 2 (s) + 6 H 2 O (l) a. Fe 2+ (aq) b. H + (aq) c. I 2 (s) d. IO 3 - (aq) Section Three 1) In an electrochemical cell, electrons flow from the a. Anode to the cathode b. Cathode to the anode c. Anode to the salt bridge d. Salt bridge to the cathode 2) In the electrochemical cell whose overall reaction is represented by the following equation, the negative electrode is Zn (s) + Cu 2+ (aq) Zn 2+ (aq) + Cu (s) a. Cu (s) b. Cu 2+ (aq) c. Zn (s) d. Zn 2+ (aq) 3) In the zinc-carbon cell, the anode is ___ and the cathode is ___.
Image of page 6
Image of page 7
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern