acceleration The physical quantity is acceleration as indicated in the Section

Acceleration the physical quantity is acceleration as

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acceleration The physical quantity is acceleration, as indicated in the Section 1.3 of the text. By observing the Velocity vs. Time graph in Step 3 of the instructions, what is the value of the slope of this line? 0 m/s^2 The horizontal Velocity vs. Time graph has a slope of zero confirming the fact that the speed is constant and the acceleration is zero. Complete Table 2. Record all data to three decimal places (e.g., 4.000 or 6.325 or 0.000). Do not include units in your answer. Table 2 Initial Settings At (m) Time (s) Calculated Position (m) Calculated Velocity (m/s) Describe 20 6.325 Measure values to 3 decimal places. 20.003 Use 6.325 Use Position ( x ) vs. Time graph increasing parabolic curve Since the car is accelerating, the distance traveled each second increases as the square of the time, so the curve is parabolic. 40 8.944 Measure values to 3 decimal places. 39.998 Use 8.944 Use Velocity ( v ) vs. Time graph increasing straight line The velocity increases the same amount each second, so the velocity vs. time graph is a straight line. 50 10.000 Measure values to 3 decimal places. 50.000 Use 10.000 Use Acceleration ( a ) vs. Time graph horizontal line Since acceleration does not change with time, its graph is a horizontal line. 20 4.472 Measure values to 3 decimal places. 19.999 Use 8.944 Use Position ( x ) vs. Time graph increasing parabolic curve Since the car is accelerating, the distance traveled each second increases as the square of the time, so the curve is parabolic. 40 6.325 Measure values to 3 decimal places. 40.006 Use 12.650 Use Velocity ( v ) vs. Time graph increasing straight line The velocity increases the same amount each second, so the velocity vs. time graph is a straight line. 50 7.071 Measure values to 3 decimal places. 49.999 Use 14.142 Use Acceleration ( a ) vs. Time graph horizontal line Since acceleration does not change with time, its graph is a horizontal line. I observed that as time increased, the velocity vector decreased in length. Since the acceleration was constant, the velocity vector changed (increased). I observed that as time increased, the acceleration vector stayed the same length. The acceleration was constant, so it did not change. x = 0.00 m v = 0.00 m/s a = 1.00 m/s 2 d = ½ at 2 . v = at . d = ½ at 2 . v = at . d = ½ at 2 . v = at . x = 0.00 m v = 0.00 m/s a = 2.00 m/s 2 d = ½ at 2 . v = at . d = ½ at 2 . v = at . d = ½ at 2 . v = at . True False True False
1/21/2018 Module 1 - Experiment - Motion 3/4 Part III: Data Part III: Questions Show My Work (Optional) 2. 1.38/1.38 points | Previous Answers ERAUColPhysMechL1 2.1.POST.001. A car starts at position with an initial velocity of 2.6 m/s and an acceleration of 0 m/s 2 . What is its position when the elapsed time is 3.2 s? (Please be sure to include units in your answer. Express your answer to one decimal point.) 8.3 m Show My Work (Optional) Please include units in your answer.

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