{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

If we were to make n loops of this wire then our

Info icon This preview shows pages 14–19. Sign up to view the full content.

View Full Document Right Arrow Icon
where A is the area of the loop. If we were to make N loops of this wire then our equation would become: τ tot = NIAB sin θ
Image of page 14

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
. . Current Loop B B I F F I I
Image of page 15
Magnetic Moment The first part of right side of the last equation (NIA) is dependent on properties of the loop. Because of this we define the magnetic dipole moment vector, μ , of the wire: The magnetic dipole moment vector points perpendicular to the plane of the loop(s), a normal so to speak. μ = NIA
Image of page 16

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Magnetic Moment The angle θ will be between μ and B such that: τ = μ × B = μ B sin θ A magnetic dipole moment located in an external magnetic field will have a magnetic potential energy, U. U will depend on the dipole’s orientation in the field, such that: U will be least value when μ and B are parallel. U will be greatest when μ and B are anti- parallel.
Image of page 17
Electric Motor An application of this concept is the electric motor. An electric motor converts electrical energy to mechanical energy (specifically rotational kinetic energy). A simple electric motor consists of a rigid current- carrying loop that rotates when placed in a magnetic field. To provide continuous rotation in one direction, the current loop must periodically reverse, (AC current).
Image of page 18

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
For Next Time (FNT) Start reading Chapter 29 Keep working on the homework for Chapter 28
Image of page 19
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern