b P B A P A B P A P A B P B 1 P A 14 2 522 1 482 52 2 1 33 12 LetP j She passes

B p b a p a b p a p a b p b 1 p a 14 2 522 1 482 52 2

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b.P(B|A) =P(AB)P(A)=P(A|B)P(B)1-P(¯A)=(1)42/5221-482/522=13312. LetPj={She passes thejthexam}. 18. LetI={Independent},L={Liberal}, andC={Conservative}.L,I, andCforma partition of the entire sample space. 2
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  • Spring '08
  • G.JOGESHBABU
  • Conditional Probability, Probability theory, Bayesian probability, AirTrain Newark, Bayes Theorem

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