00 L of methanol are reacted with 800 kg of oxygen a What is the limiting

00 l of methanol are reacted with 800 kg of oxygen a

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In a particular reaction 2.00 L of methanol are reacted with 80.0 kg of oxygen. a. What is the limiting reactant? (5 points) b. What reactant and how many grams of it are left over? (5 points) c. How many grams of carbon dioxide is produced? (5 points) a. 1580g Meth compared to 2370 Oxy - Methanol is the limiting reactant b. D = M / V .79 g / m ( 2000 )= 1580 gm 2mols Meth/3mols Oxy Met h 32 = 1 mol 1580 32 = 49.38 3 ( 49.38 ) 2 = 74.06 g Oxy 32 = 1 mol 74.06 ( 32 ) = 2370 g 4 Copyright © 2017 by Thomas Edison State University . All rights reserved.
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80kg=80000g 80,000-2370= 77,630g excess c. 2 Meth/2 CO2 1 mol CO2=44g 49.38*44= 2172.72g 11. An iron bar weighed 664 g. After the bar had been standing in moist air for a month, exactly one-eighth of the iron turned to rust (Fe 2 O 3 ). Calculate the final mass of the iron bar and rust. (5 points) Balanced Fe + 3 4 O 2 1 2 Fe 2 O 3 mass Fe 2 O 3 = ( 2 ) 55.85 + 3 ( 16 ) = 159.7 159.7 2 = 79.85 56 g Fe→ 79.85 g F e 2 O 3 1 8 664 = 83 83 80 63 = 118.57 gF e 2 O 3 664 Fe 118.57 = 545.43 g Fe (Reference: Chang 3.111) 5 Copyright © 2017 by Thomas Edison State University . All rights reserved.
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