Question 12 of 20 50 50 points solve 27 x 3x 3 a 1 b

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PART 2 EXAM 6

Question 12   of 20 5.0 / 5.0 Points Solve : 2 ( 7 – x ) = 3 ( x + 3 )
A. – 1
B. 1
C. 
D. 5
Question 13   of 20 5.0 / 5.0 Points Simplify : ( 2.4 ) ( a – 0.2 b + 3.5 c )
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Question 16   of 20 5.0 / 5.0 Points The perimeter of a rectangle is 90 cm . It s width is half its length . Which equation could be solved to find the dimensions of the rectangle ?
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Question 17   of 20 5.0 / 5.0 Points Solve : 5 ( x + 9 ) – 23 = 42
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Question 18   of 20 5.0 / 5.0 Points Solve : 3 x + 31 = x – 25
A. 28
B. – 28
C. 13
Question 19   of 20 5.0 / 5.0 Points Solve : –x – 7 = – 2x – 11
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Question 12 of 20 5.0/ 5.0 Points Solve: 2(7 – x) = 3(x + 3) A. –1 B. 1 C. D. 5
Question 13 of 20 5.0/ 5.0 Points Simplify: (2.4)(a – 0.2b + 3.5c)
Question 14 of 20 5.0/ 5.0 Points
Simplify: 19x – y – 2z + x + 5y + 2z
Question 15 of 20 5.0/ 5.0 Points Five times a number plus four times the same number is equal to 360. What is the number?
Question 16 of 20 5.0/ 5.0 Points The perimeter of a rectangle is 90 cm. Its width is half its length. Which equation could be solved to find the dimensions of the rectangle? A.
B. C. 2L + 2(L – 2) = 90 D. 2L + 2(L + 2) = 90 Question 17 of 20 5.0/ 5.0 Points Solve: 5(x + 9) – 23 = 42
Question 18 of 20 5.0/ 5.0 Points Solve: 3x + 31 = x – 25
D. 16 Question 19 of 20 5.0/ 5.0 Points Solve: –x – 7 = –2x – 11
Question 20 of 20 5.0/ 5.0 Points A man’s suit was on sale for 15% off the regular price. The sale price was $216.75. What was the regular price? A. $249.26 B. $250 C. $225 D. $255

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