# A mean that is in a confidence interval is not

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302.438 - 326.184 300.618 - 330.182 297.485 - 327.820 282.871 - 338.475 Use =CONFIDENCE.T(0.1,43.2,25), then add and subtract the result from the sample mean to find the lower and upper limits of the interval
No, because 300 is below the lower limit of the confidence interval Yes, because 300 is below the lower limit of the confidence interval No, because 300 is in the confidence interval Yes, because 300 is in the confidence interval
A mean that is in a confidence interval is not rejected by the confidence interval, and we say the evidence against the mean is not significant. At the 0.05 level of significance, is there evidence against mean \$300?
Hide Feedback No, because 300 is below the lower limit of the confidence interval Yes, because 300 is below the lower limit of the confidence interval No, because 300 is in the confidence interval Yes, because 300 is in the confidence interval Feedback: Find the interval width with =CONFIDENCE.T(0.05,75,25). Then add and subtract this from the mean, 315.40. The interval is 284.442 - 346.358 The value of 300 is inside the interval, so we have no evidence that the actual population mean is over 300.
Question 15 7 / 7 points Explain the difference between parts A and C. In both parts we are asked whether or not there is evidence that the population mean was over \$300. Hide Feedback
Attempt Score: 100 / 100 - 100 % Overall Grade (highest attempt) : 100 / 100 - 100 % Done