b Predicted boiling point highest to lowest F E D Elution order first to last D

B predicted boiling point highest to lowest f e d

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b. Predicted boiling point: (highest to lowest) F, E, D Elution order: (first to last) D, E, F Example F has the highest boiling point because it has 2 hydrogen bonds with no branching, E has the middle boiling point because it has 2 hydrogen bonds with 1 of them being branched of the carbon chain, and D has the lowest boiling point because it only has 1 hydrogen bond in it. The elution order from first to last is the same as the boiling points from the lowest to the highest. This is because a compound will elute faster if it has a lower boiling point. When the temperature in the gas chromatography increases the compound with the lowest boiling point will evaporate first, and therefore elute first. 3. Refer back to the list of five important structural characteristics you generated in Section I of the lab. Do these predictions match the experimental data obtained in lab? Why or why not? If needed, make a new list that agrees with the data. The predictions match fairly closely to the experimental data that was obtained in this lab. This is because I nearly had my list in the right order, but I should have put branching behind molecular weight and size. The fact that I made intermolecular forces the most important factor in my list and that each of the compounds I was given had similar molecular weights made my predictions match the data that I obtained. However the order of my list may not have worked for compounds with the same intermolecular forces and different molecular weights. My new list in order from the most important to the least important factors of boiling points would be intermolecular forces, polarity, molecular weight, molecular size, and then branching.
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