See Sec 52 of Zumdahl Chemistry Volume of room 16ft12ft12ft 2304 ft 3 Room gas

See sec 52 of zumdahl chemistry volume of room

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See Sec. 5.2 of Zumdahl, ChemistryVolume of room = 16ft*12ft*12ft = 2304 ft3Room gas volume at lower temp (V2) = V1(T2/T1) = 2304(270/300) = 2097 ft32304-2097 = 210 ft must enter room to compensate.30. ANS: 2See Sec. 5.5 of Zumdahl, ChemistryRatio of partial pressures will be same as ratio of mole fractions.mole fraction H2: mole fraction He = XH2/2.016 : XHe/4.003, which reduces to 2:131. ANS: E 32. ANS: D .PTS: 1 DIF: Moderate REF: 5.2 KEY: Chemistry | general chemistry | phases | gas | empirical gas laws | Charles's lawMSC: Conceptual.PTS: 1 DIF: Moderate REF: 5.5 KEY: Chemistry | general chemistry | phases | gas | gas mixtures | Dalton's law of partial pressuresMSC: QuantitativePTS: 1 DIF: Moderate REF: 5.1KEY: Chemistry | general chemistry | phases | gas | gas pressure MSC: QuantitativePTS: 1 DIF: Moderate REF: 5.7KEY: Chemistry | general chemistry | phases | gas | molecular speed | diffusionMSC: Conceptual

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