CHE4284_5292_Problems_20130522_Solution

# Far a 01 x 005 0 15 x 015 03 x 065 045 x 001 0227 far

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FAR A = (0.1 x 0.05) + (0 .15 x 0.15) + (0.3 x 0.65) + (0.45 x 0.01) = 0.227 FAR B = (0.1 x 0.01) + (0.35 x 0.15) + (0.1 x 0.65) + (0.45 x 0.30) = 0.254 FAR B > FAR A barb2right Worker B is at higher risk 1.3 If there are 1000 workers in the plant, calculate the fatality rate for the whole plant. Total Hours = year hours 10 x 2 year worker hours 000 , 2 workers 1000 6 = - Number of Fatalities = fatalities x 0402 . 0 10 2 10 01 . 2 6 8 =

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CHE-4284/CHE-5292 Industrial Safety Summer 2013 Problems MEPdeF - 05/22/2013 Problem 1 (continued) Fatality Rate = year person deaths - × = - 5 10 02 . 4 1000 0402 . 0 1.4 Calculate the fatality rate for worker B, assuming that 45% of the total workers follow this shift. Total Number of Workers in Shift = 0.45 x 1,000 = 450 workers Total Hours = 450 x 2000 hours/year = 900,000 hours Number of Fatalities = fatalities 10 86 . 22 hours 000 , 900 hours 10 deaths 254 . 0 4 8 - × = Fatality Rate = year person deaths 10 08 . 5 450 10 86 . 22 6 4 - × = × - - 1.5 If in Unit 5 the number of lost workdays has been 2 in the past 120 days and the total workers in this Unit are 250, find the OSHA Incidence Rate based on lost workdays. employees all by worked hours Total 000 , 200 x days work lost of Number Rate Incidence OSHA = OSHA = 67 . 1 hours 8 day days 120 s ker wor 250 hours 000 , 200 days work lost 2 =
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