# Start amounts invested x y end of 1 year interest

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Start-amounts invested X Y End of 1 year - interest 0.05X 0.05Y Amount at the beginning of II year 21.05X1.05Y - 11,500 (withdrew 50%) (withdrew Rs. 11,500) Interest during the II year 0.05 x 21.05X0.05 x (1.05Y - 11,500) Amount at the end of II year ()2X1.0521.05(1.05Y - 11,500) Beginning of III year (()2X1.052- 4,050) 1.05(1.05Y - 11,500) Interest during the III year 0.05(()2X1.052- 4,050) 0.05 x 1.05(1.05Y-11,500) Total amount at III year end 1.05 (()2X1.052- 4,050) 1.052x (1.05Y - 11,500) Given : Total amount with Prem at the end of third year = Total amount with Amar at the end of second year.
© A. Krishnamurthy M.Sc. M.Phil Reproduction of this in any form without express permission is strictly prohibited. Notes are not for public distribution and are intended to supplement class room instruction.Mail-Id:[email protected]87(1.05)2x (1.05Y - 11,500) = ()2X1.052- (1) Also given : Total interest earned by Amar for 3 years = Rs.3,950. 0.05X + 21.05Xx0.05+ 0.05 ()2X1.052- 4050) = 3950 Solving X = Rs.40,000. Using this value of X in (1), we get the value of Y = Rs.30,000 1. (2) Rs. 40,000 2. (3) Rs. 30,000 3. (1) Total interest earned by Prem = 0.05Y + 0.05(1.05Y - 11,500) + 0.05 x 1.05(1.05Y - 11,500) = Rs. 3550 4. (2) Interest earned by Amar in the III year is 0.05 (()2X1.052- 4,050) = Rs. 900 5. (1) Prem would have had Rs. 30,000 x 1.053= Rs. 34,728 Questions 6 - 10: M = Retirement money Fixed Deposits Shares Initial 0.60M 0.40M Return during 1styear 0.15 x 0.60M = 0.09M 0.25 x 0.40M = 0.10M Total at start of 2ndyear 0.60M - 0.25 x 0.60M 0.40M + 0.10M + 0.15M = 0.60M – 0.15M = 0.65M = 0.45M Return in the 2ndyear 0.15 x 0.45M -(0.1 x 0.65M) = -(0.065M) Net amount at start of 3rdyear 0.45M + 0.15M (returned) 0.65M – 0.065M = 0.60M = 0.595M Return during the 3rdyear 0.15 x 0.60M 0.1 x 0.595M = 0.0595M Net profit earned through shares in three years = 0.10M - 0.065M + 0.0595M = 18,900 M = Rs.2,00,000
© A. Krishnamurthy M.Sc. M.Phil Reproduction of this in any form without express permission is strictly prohibited. Notes are not for public distribution and are intended to supplement class room instruction.Mail-Id:[email protected]886. (2) 7. (1) Amount of interest earned = 0.15 x 0.6M + 0.15 x 0.45M + 0.15 x 0.6M = 0.15 x 1.65M = Rs.49,500 8. (3) Loss incurred = 0.1 x 0.65 M = Rs.13,000 9. (1) Investment in shares in the third year = 0.435M = Rs.87,000 10. (1) Average annual return = 3x200000sharesonProfit+interestTotal=3x20000015700+49500= 10.8% Questions 11 - 15: A B C X 10 hrs 20 hrs 15 hrs Y 12 hrs 15 hrs 24 hrs No. of machines 2 3 4 Working hours per day = 8 11. (2) Total number of working hours per machine per month = 25 x 8 = 200 Total number of hours available on A = 2 x 200 = 400 hrs, B = 3 x 200 = 600 hrs, C = 4 x 200 = 800 hrs No. of units of X that can be produced on A = 10400= 40, B = 20600= 30, C = 15800= 53 Maximum number of pieces that can be produced is the least of these three i.e., 30. 12. (1) No. of Y’s total that can be produced on A = 12400= 33, B = 15600= 40, C = 24800= 33 Max. No. of Y’s that can be produced is 33. 13. (3)
© A. Krishnamurthy M.Sc. M.Phil Reproduction of this in any form without express permission is strictly prohibited. Notes are not for public distribution and are intended to supplement class room instruction.Mail-Id:[email protected]89No. of hrs required to produce 20 units of X Balance hours left in the month A 10 x 20 = 200 hrs 400 - 200 = 200 hrs B 20 x 20 = 400 hrs 600 - 400 = 200 hrs C 15 x 20 = 300 hrs 800 - 300 = 500 hrs No. of Y’s that can be produced in the balance hours.

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