Case 2 Selection 1 Start again with the initial genotype and produce offspring

Case 2 selection 1 start again with the initial

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Case 2 (Selection) 1. Start again with the initial genotype, and produce “offspring,” as in Case 1. 2. Offspring with genotype aa will not survive in this simulatrion. Thus, in order to maintain population size, parents must continue mating until they produce two surviving offspring. 3. Proceed through five generations, selecting against the homozygous offspring 100% of the time. Then add up the genotype frequencies that exist in the population and calculate the new p and q frequencies, as done in Case 1. Case 3 (Heterozygous Advantage) 1. In this round, keep everything the same as it was in Case 2, but flip a coin whenever an AA offspring is obtained. If the coin lands on heads, the offspring does not survive. 2. Simulate for five generations, starting with the initial genotype from Case 1. [Genotype AA only survives when the coin toss results in tails, genotype aa never survives.] Partners must continue mating until they produce two surviving offspring.
3. Get new allele cards as needed. Total the class genotype results and calculate the p and q frequencies. 4. Starting with the F5 genotypes, go through five more generations, and again total the genotypes and calculate the p and q frequencies/. Case 4 (Genetic Drift) 1. Divide the lab into several smaller populations so that individuals from one population do not interact with those of another. 2. Go through five generations and record new p and q frequencies for each population.

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