# B consider the situation when friction force is non

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(b) Consider the situation when friction force is non-zero. What is the expression for theacceleration of the cart now? (Use the following as necessary: m1, m2, f, and g.) 2)If you now triple the hanging mass m1, (so m= 3m1) how will the value of the denominator forthe expression for the acceleration change?What is the expression for the acceleration now? (Use the following as necessary: m1, m2, f, andg.) 2) Based on your answers to the previous parts, what conclusion can you draw about theacceleration of the cart?Additional Materials.
3/27/2019Lab 3 - Newton's Second Law: PostLab8/124.10/10 points | Previous AnswersIn the diagram below, indicates the pulling force and the friction force acting on the object. Thedirection of motion of the object is indicated by the velocity vector .Figure AFigure BFigure CFor each case, indicate the direction of the net force, the direction of the acceleration of the object andstate whether the object is speeding up, slowing down, or moving with constant velocity. The forcevectors are drawn to scale.Direction of net forceDirection of accelerationThe object isAto the left to the leftto the left to the leftslowing down slowing downBto the right to the rightto the right to the rightspeeding up speeding upCThe net force is zero. The net force is zero.The acceleration is zero. The acceleration is zero.moving with constant velocity moving with constant velocityAdditional MaterialsNewton's Second LawAppendix
3/27/2019Lab 3 - Newton's Second Law: PostLab