The following crosses were made to determine the genetics of this trait Last

The following crosses were made to determine the

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(strain B). The following crosses were made to determine the genetics of this trait. Last term this was the bonus question for the second test. Cross #1 Parents Strain A female x Strain B male all F1 females lay white eggs Cross #2 Parents Strain B female x Strain A male all F1 females lay blue eggs The F1 from cross #1 were intercrossed and the following was found. ½ of the F2 females layed white eggs and ½ of the females layed blue eggs. The F2 from cross #2 were intercrossed and the same results were found, ½ of the F2 females layed white eggs and ½ of the females layed blue eggs. a) Assuming that one gene is involved give genotypes for the males and females, for crosses 1 and 2 and also for the F1 crosses to produce the F2. Cross #1 Parents Strain A female x Strain B male all F1 females lay white eggs Z b W Z w Z w Z w W males are Z b Z w Cross #2 Parents Strain B female x Strain A male all F1 females lay blue eggs Z w W Z b Z b Z b W males are Z b Z w F1 from Cross #1 Z w W x Z w Z b Z w W Z b W Z w Z b Z w Z w Female who lays white eggs Female who lays blue eggs males who do not lay eggs F1 from Cross #1 Z b W x Z w Z b Z w W Z b W Z w Z b Z b Z b Female who lays white eggs Female who lays blue eggs males who do not lay eggs b) Which allele is dominant, the blue or the white allele? In order to tell which allele is dominant, you need to look at the heterozygote. Only the male is heterozygous but the male does not lay eggs. It is not possible to tell. Only the female lays eggs and she only has one allele.
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  • Spring '11
  • dr
  • Gamete, Zb Zw

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