MSE
MSE 331 Midterm Examination –I(2018) Key .pdf

# 4 point each 16 points abc 111 acd 001 adb 100 bcd

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(4 point each = 16 points) (ABC) = (111) (ACD) = (001) (ADB) = (100) (BCD) = (010) (3) On the (010) stereographic projection drawn in (1), plot the poles correspond to (ABC), (ACD), (ADB) and (BDC) planes. If you can not find the pole(s) that corresponds to the plane(s), explain why. (4 point each = 16 points) Shown in figure above (4) Draw (1 2 2) plane in the figure shown in (2). (5 points) Miller index 1 2 2 Reciprocal 1/1 1/½ 1/½ Intercept 1 ½ ½ (5) Plot an (122) pole by Å on the (010) stereographic projection drawn in (1). (5 points) (122) pole should be on the great circle between (011) and (111) poles. Angle between (011) and (122) can be found from (011)•(122)=| 0 1 1|•|2 1 2|cos q Solve for q , then you get q ~19.5˚ The pole (122) exists 19.5˚ off from the (011) pole on the great circle This is shown by yellow dot ( Å ) . (6) Find the trace of (01-1) pole on the (010) stereographic projection shown in (1). (5 points) Trace line is a great circle 90˚ from the (01-1) pole as shown by pink line . (7) Which major poles are on the trace you determined? (5 points) (-100) (-111) (011) (111) and (100) (122) pole is also on the same trace. (8) Next, construct the (011) pole stereographic projection (with the North and South poles remained same) from (1), and show all the major poles. C A B D x y z C A B D x y z ½ ½

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(15 points) [3]. Find the Miller index of the plane ABC and the crystallographic direction CA (i.e. from C to A) using a 4 digit coordinate of the hexagonal system.
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