These are the parametric equations for the motion of

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θx
(c) What is the horizontal velocity ifA=45 degrees?
(These are the parametric equations for the motion of the stunt cyclist.)(a) Calculate the horizontal velocity of the cyclist at timet; this is the functionx'(t)$$100cos(A).(b) What is the horizontal velocity ifA=20 degrees?=
$$70.711(Four decimal places.)(d) Calculate the vertical velocity of the cyclist at timet; this is the functiony'(t)=
(e) What is the vertical velocity ifA=20 degrees?
(f) What is the vertical velocity ifA=45 degrees?
(Four decimal places.)(g) The vertical velocity of the cyclist is zero at time$$3.125sin(A)seconds.(h) If the cyclist wants to have a maximum height of 35 feet above the landing zone, then the required launch angle isA=$$23.5782degrees. (Accurate to four decimal places.)
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Term
Spring
Professor
WAlker
Tags
Math, Calculus, Derivative, Acceleration, Velocity, Parametric equation, Vertical direction

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