$$70.711(Four decimal places.)(d) Calculate the vertical velocity of the cyclist at timet; this is the functiony'(t)=
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(e) What is the vertical velocity ifA=20 degrees?
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(f) What is the vertical velocity ifA=45 degrees?
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(Four decimal places.)(g) The vertical velocity of the cyclist is zero at time$$3.125sin(A)seconds.(h) If the cyclist wants to have a maximum height of 35 feet above the landing zone, then the required launch angle isA=$$23.5782degrees. (Accurate to four decimal places.)