# These are the parametric equations for the motion of

• Homework Help
• 7
• 100% (12) 12 out of 12 people found this document helpful

This preview shows page 6 - 7 out of 7 pages.

θx
(c) What is the horizontal velocity ifA=45 degrees?
(These are the parametric equations for the motion of the stunt cyclist.)(a) Calculate the horizontal velocity of the cyclist at timet; this is the functionx'(t)\$\$100cos(A).(b) What is the horizontal velocity ifA=20 degrees?=
\$\$70.711(Four decimal places.)(d) Calculate the vertical velocity of the cyclist at timet; this is the functiony'(t)=
(e) What is the vertical velocity ifA=20 degrees?
(f) What is the vertical velocity ifA=45 degrees?
(Four decimal places.)(g) The vertical velocity of the cyclist is zero at time\$\$3.125sin(A)seconds.(h) If the cyclist wants to have a maximum height of 35 feet above the landing zone, then the required launch angle isA=\$\$23.5782degrees. (Accurate to four decimal places.)
End of preview. Want to read all 7 pages?