b Element 119 c Element 115 would be found directly below Bi and would be a

# B element 119 c element 115 would be found directly

• DePaul University
• CHE 130
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• miny1229
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(b) Element 119 (c) Element 115 would be found directly below Bi and would be a metal. Element 117 might have the properties of a semimetal. (d) Element 119, at the bottom of group 1A, would likely be a soft, shiny, very reactive metal forming a +1 cation. 1.94 NaCl melting point = 1074 K o C = K S 273.15 = 1074 S 273.15 = 800.85 o C = 801 o C o o o o 9 9 F = ( x C) + 32 = ( x 800.85) + 32 = 1473. F = F 53 1474 5 5 NaCl boiling point = 1686 K o C = K S 273.15 = 1686 S 273.15 = 1412.85 o C = 1413 o C o o o o 9 9 F = ( x C) + 32 = ( x 1412.85) + 32 = 2575. F = F 13 2575 5 5 1.95 o o o 9 9 F = x C + 32 = x (_ 38.9) + 32 = _ 38. F 0 5 5 1.96 1 mL V = 112.5 g x = 75.85 mL 1.4832 g 1.97 lb 453.59 g 1 gal 1 L 15.28 x x x = 1.831 g / mL gal 1 lb 3.7854 L 1000 mL Chapter 1 S Chemistry: Matter and Measurement _____________________________________________________________________________ 15 1.98 10 10 453.59 g 1 mL 1 L V = 8.728 x lb x x x = 2.162 x L 10 10 1 lb 1.831 g 1000 mL 1.99 2.54 cm 10 mm 0.22 in x x = 5.6 mm 1 in 1 cm 1.100 (a) density = 1 lb 8 pints 1 gal 453.59 g 1 L x x x x 1 pint 1 gal 3.7854 L 1 lb 1000 mL = 0.95861 g/mL (b) area in m 2 = 2 2 2 2 2 1 5280 ft 12 in 2.54 cm 1 m mi 1 acre x x x x x 640 acres 1 mi 1 ft 1 in 100 cm = 4047 m 2 (c) mass of wood = 3 3 3 3 128 12 in 2.54 cm 0.40 g 1 kg ft 1 cord x x x x x 1 cord 1 ft 1 in 1 1000 g cm = 1450 kg = 1400 kg (d) mass of oil = 42 gal 3.7854 L 1000 mL 0.85 g 1 kg 1 barrel x x x x x 1 barrel 1 gal 1 L 1 mL 1000 g = 135.1 kg = 140 kg (e) fat Calories = 32 servings 165 Calories 30.0 Cal from fat 0.5 gal x x x 1 gal 1 serving 100 Cal total = 792 Cal from fat 1.101 amount of chocolate = 105 mg caffeine 1.0 ounce chocolate 2.0 cups coffee x x 1 cup coffee 15 mg caffeine = 14 ounces of chocolate 14 ounces of chocolate is just under 1 pound. 1.102 (a) number of Hershey = s Kisses = 453.59 g 1 serving 9 kisses 2.0 lb x x x 1 lb 41 g 1 serving = 199 kisses = 200 kisses (b) Hershey = s Kiss volume = 41 g 1 serving 1 mL x x 1 serving 9 kisses 1.4 g = 3.254 mL = 3.3 mL (c) Calories/Hershey = s Kiss = 230 Cal 1 serving x 1 serving 9 kisses = 25.55 Cal/kiss = 26 Cal/kiss (d) % fat Calories = 13 g fat 9 Cal from fat 1 serving x x x 100% 1 serving 1 g fat 230 Cal total = 51% Calories from fat 1.103 Let Y equal volume of vinegar and (422.8 cm 3 S Y) equal the volume of oil. Mass = volume x density 397.8 g = (Y x 1.006 g/cm 3 ) + [(422.8 cm 3 S Y) x 0.918 g/cm 3 ] 397.8 g = (1.006 g/cm 3 )Y + 388.1 g S (0.918 g/cm 3 )Y Chapter 1 S Chemistry: Matter and Measurement _____________________________________________________________________________ 16 397.8 g S 388.1 g = (1.006 g/cm 3 )Y S (0.918 g/cm 3 )Y 9.7 g = (0.088 g/cm 3 )Y Y = vinegar volume = 3 9.7 g 0.088 g/ cm = 110 cm 3 oil volume = (422.8 cm 3 S Y) = (422.8 cm 3 S 110 cm 3 ) = 313 cm 3 1.104 o o 5 C = x F _ 32) ( 9 ; o o Set C = F: o o 5 C = x C _ 32) ( 9 o o o o o o o o 9 Solve for C: C x = C _ 32 5 9 C x ) _ C = _ 32 ( 5 4 C x = _ 32 5 5 C = (_ 32) = _ 4 C 0 4 The Celsius and Fahrenheit scales A cross @ at o o _ C (_ F). 40 40 1.105 Cork: volume = 1.30 cm x 5.50 cm x 3.00 cm = 21.45 cm 3 mass = 3 3 0.235 g 21.45 x = 5.041 g cm 1 cm Lead: volume = (1.15 cm) 3 = 1.521 cm 3 mass = 3 3 11.35 g 1.521 x = 17.26 g cm 1 cm total mass = 5.041 g + 17.26 g = 22.30 g total volume = 21.45 cm 3 + 1.521 cm 3 = 22.97 cm 3 average density = 3 3 22.30 g = 0.971 g/ cm 22.97 cm so the cork and lead will float. 1.106 Convert 8 min, 25 s to s. 60 s 8 min x 1 min + 25 s = 505 s Convert 293.2 K to o F 293.2 S 273.15 = 20.05 o C o o 9 F = ( x 20.05) + 32 = 68. F 09 5 Final temperature = 68.09 o F + o o 3. F 0 505 s x = 93. F 34 60 s o C = o 5 x (93.34 _ 32) = 34. C 1 9 1.107 Ethyl alcohol density = 19.7325 g 25.00 mL = 0.7893 g/mL total mass = metal mass + ethyl alcohol mass = 38.4704 g Chapter 1 S Chemistry: Matter and Measurement _____________________________________________________________________________ 17 ethyl alcohol mass = total mass S metal mass = 38.4704 g  #### You've reached the end of your free preview.

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