# This fit is a more precise way of ob taining both ω

This preview shows pages 1–2. Sign up to view the full content.

What do each of the fitting parameters represent? This fit is a more precise way of ob- taining both ω and τ than in the previous sections. The over-damped signal is simpler than the under-damped one. Save your data. Fit it to the following, mathematical expression with fitting parameters A and B: V ( t ) = Ae - Bt/ 2 (2) Again, what do each of the fitting parameters represent? Is the value you get for τ con- sistent with what you calculated theoretically? 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Critically Damped ...Measure the resistance of the Decade Box using your DMM and determine what the total resistance ( R tot = R dec + R sig + R L ) is for this circuit. This is your empirical value for R crit . Compare this with the theoretical value given by Eq. ?? . Is your value within the expected error? 3 Driven LRC circuit Sweep the driving frequency while watching the amplitude of the V R response. Roughly locate the frequency at which | V R | is maximal. This should correspond approximately to the theoretical value of ω 0 / 2 π . Are the two in agreement with one another? Locate the two “half power” points above and below the resonant frequency; these are the frequencies at which the amplitude of oscillation is V max / 2, where V max is the amplitude at resonance (Fig. ?? ). Since power ∝ | I | 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern