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), load resistor (RL), ammeter, and voltmeter. The equation ࠵? =KLMLNMO-∗ ࠵?,gives the power dissipated in the load resistor. R0was measured to be 100 Ωand then current-voltage data was recorded as the value of RLwas changed. RLwas in increments of 10 Ωfrom 10-120 Ω; increments of 20 Ωfrom 120-200 Ω; and increments of 100 Ωfrom 200-1000 Ω. The power dissipated was calculated with the equation ࠵? = ࠵? ∗ ࠵?and a graph of P vs. RLwas plotted. The graph was fitted to the form ࠵? ∗JPN3-.The load resistance that maximizes power output was roughly 110 Ω. The calculated efficiency of our circuit was 52.36%. One source of error for our group was that for part 2 we used a different value of V0which still worked but, changed our numbers and results from the rest of the groups. Another source of error could come from improperly setting up the circuit and measuring the wrong values. It’s important to follow the directions and set things up in the right order.