AB 7 8 9 BC 4 13 m B 33 7 m C 56 3 10 acute 11 right Pythagorean triple 12

Ab 7 8 9 bc 4 13 m b 33 7 m c 56 3 10 acute 11 right

This preview shows page 100 - 105 out of 134 pages.

AB = 7 . 8 9. BC = 4 13 , m B = 33 . 7 , m C = 56 . 3 10. acute 11. right, Pythagorean triple 12. obtuse 13. right 14. acute 15. obtuse 16. x = 2 17. x = 2 110 18. x = 6 7 19. 2576.5 ft. 20. x = 29 . 2 21. AC = 16 . 1 , m A = 41 . 6 , m C = 63 . 4 22. m A = 123 . 7 , m B = 26 . 3 , m C = 30 92
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Chapter 9 Geometry - Second Edition, Chapter 9, Answer Key 9.1 Geometry - Second Edition, Parts of Circles and Tangent Lines, Review Answers 1. diameter 2. secant 3. chord 4. point of tangency 5. common external tangent 6. common internal tangent 7. center 8. radius 9. the diameter 10. 4 lines 11. 3 lines 12. none 93
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13. radius of B = 4 , radius of C = 5 , radius of D = 2 , radius of E = 2 14. D E because they have the same radius length. 15. 2 common tangents 16. CE = 7 17. y = x 2 18. yes 19. no 20. yes 21. 4 10 22. 4 11 23. x = 9 24. x = 3 25. x = 5 26. x = 8 2 27. (a) Yes, by AA. m CAE = m DBE = 90 and AEC BED by vertical angles. (b) BC = 37 (c) AD = 35 (d) m C = 53 . 1 28. Table 9.1: Statement Reason 1. AB and CB with points of tangency at A and C . AD and DC are radii. Given 2. AD DC All radii are congruent. 3. DA AB and DC CB Tangent to a Circle Theorem 4. m BAD = 90 and m BCD = 90 Definition of perpendicular lines 5. Draw BD . Connecting two existing points 6. ADB and DCB are right triangles Definition of right triangles (Step 4) 7. DB DB Reflexive PoC 8. ABD CBD HL 9. AB CB CPCTC 29. (a) kite (b) center, bisects 30. AT BT CT DT by theorem 10-2 and the transitive property. 31. 9.23 32. 8 3 ; 8 3 3 33. Since ←→ AW and ←→ WB both share point W and are perpendicular to VW because a tangent is perpendicular 94
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to the radius of the circle. Therefore A , B and W are collinear. VT VW because they are tangent segments to circle A from the same point, V , outside the circle. Similarly, VW VU because they are tangent segments to circle B from V . By the transitive property of congruence, VT VU . Therefore, all three segments are congruent. 9.2 Geometry - Second Edition, Properties of Arcs, Review Answers 1. minor 2. major 3. semicircle 4. major 5. minor 6. semicircle 7. yes, d CD d DE 8. 66 9. 228 10. yes, they are in the same circle with equal central angles 11. yes, the central angles are vertical angles, so they are equal, making the arcs equal 12. no, we don’t know the measure of the corresponding central angles. 13. 90 14. 49 15. 82 16. 16 17. 188 18. 172 19. 196 20. 270 21. x = 54 22. x = 47 23. x = 25 24. A B 25. 62 26. 77 27. 139 28. 118 29. 257 30. 319 31. 75 32. 105 33. 68 34. 105 35. 255 36. 217 95
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9.3 Geometry - Second Edition, Properties of Chords, Review Answers 1. No, see picture. The two chords can be congruent and perpendicular, but will not bisect each other. 2. AC 3. d DF 4. c JF 5. DE 6. HGC 7. AGC 8. AG , HG , CG , FG , JG , DG 9. 107 10. 8 11. 118 12. 133 13. 140 14. 120 15. x = 64 , y = 4 16. x = 8 , y = 10 17. x = 3 26 , y 12 . 3 18. x = 9 5 19. x = 9 , y = 4 20. x = 4 . 5 21. x = 3 22. x = 7 23. x = 4 11 24. m c AB = 121 . 3 25. m c AB = 112 . 9 26. BF FD and c BF d FD by Theorem 10-5.
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  • Spring '14
  • Gee,Carol
  • Geometry, Edition, triangle, Supplementary Angles

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