# Tutorial the problem parts plus the hints in

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2.Tutorial (the problem parts plus the hints in MasteringPhysics walk you through how to do it)3.Problem 1.02(a) The motion diagrams are shown below.(b) In the reference frame of runner 1, he sees runner 2 coming toward him at a speed equal tov1+v2=2v.4.Problem 1.11With the conversion factors for distance and time1mi=5280 ft=1.609 km=1609 m1 h=60 min=3600 swe obtain the following conversion factors for speed:
1mph=1mih1h3600s1609m1mi=0.447m/s1mph=1mih1.609km1mi=1.609km/h1km/h=1kmh1000m1km1h3600s=0.278m/s(a)36 mph=36 mph()1.609 km/h1mph=57.9 km/h=36 mph()0.447 m/s1mph=16.1m/s(b)349 km/h=349 km/h()1mph1.609 km/h=217 mph=349 km/h()0.278 m/s1km/h=96.9m/s(c)980 m/s=980 m/s()1km/h0.278 m/s=3528 km/h=3528 km/h()1mph1.609 km/h=2192mph5.Problem 1.25Sketch and translateBoth Gabriele and Xena, the objects of interest, are riding their bicycles atconstant speeds, but in opposite directions. We choose a reference frame with Earth as the object ofreference.Simplify and diagramWe assume that Gabriele and Xena are point-­‐like objects. The origin of thecoordinate system will be the zero mark on the bike path, where an observer stands, and the positivedirection will be toward east.Represent mathematicallyThe positions of Gabriele and Xena with respect to the zero mark of thebike path as a function of time are given byxGt( )=3.0×103m8.0 m/s()txXt( )=1.0×103m+6.0 m/s()tSolve and evaluate(a) The functions describing the positions of Gabriele and Xena with respect to Earth are:

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Term
Fall
Professor
GENTILE
Tags
Work, Miles per hour