Calcium Chloride (CaCl2) Ca (1.0)- Cl (3.0)= 2.0 difference (ionic) Palmitic Acid Acid CH3(CH2)14COOH C(2.5)- H(2.1)= 0.4 difference (covalent/ C(2.5)- O(3.5)= 1.0 difference (covalent)/ O(3.5)- H(2.1)= 1.4 difference (covalent) Potassium Iodide KI K(0.8) –I(2.5)= 1.7 difference (ionic) Lauric Acid CH3(CH2)10COOH C(2.5)- H(2.1)= 0.4 difference (covalent)/ C(2.5)- O(3.5)= 1.0 difference (covalent)/ O(3.5)- H(2.1)= 1.4 difference(Ionic) Sodium Chloride NaC Na(0.9)- (3.0)= 2.1 difference (ionic) Phenyl Salicylate C6H4(OH) COOC6H5 C(2.5)- H(2.1)= 0.4 difference (covalent)/ O(3.5)- H(2.1)= 1.4 difference(ionic)/ C(2.5)- O(3.5)= 1.0 difference(covalent) 3. Draw dot diagrams for each of the substances in this experiment, look up Phenyl Salicylate using the internet, make sure you translate the internet diagram into a full dot diagram covered in class.Table of Results: List both groups (experimental and theoretical) Question 1. Write a statement to summarize the properties of ionic compounds and another statement to summarize the properties of covalent compounds.
2) Possible contamination: Since we were dealing with many compounds that all physically looked similar, it was fairly easy for one to mistake one compound for another and contaminate the compounds. A suggested improvement for this would be to have labels for each compound rather than just numbers. 3) Putting too much of the compound: For some tests such as the water/ ethanol solubility tests, it was hard to see which substances were dissolved or not because my group made the mistake of putting too much of the compounds. Conclusion: In the lab, I learned that chemical compounds are combinations of atoms held by ionic and covalent bonds. I also learned that some physical properties could be used to predict the type of bond that binds the atoms of the compound.
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- Spring '10
- Chemistry, Sodium chloride, Calcium Chloride, Lauric acid, Sodium chloride Potassium, Acid Phenyl Saclicylate, Palmitic Acid Phenyl