Question 13 to find a scores deviation from the mean

Info icon This preview shows pages 3–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Question (13): To find a score’s deviation from the mean , you simply subtract the mean from the score. The deviation may be positive, or it may be negative. Use this information to fill in the first three columns of the table on the following page. Question (14): Square each of the terms in the Deviation column of your table from question (13) to fill out the last column of the table. Add all of these squares and divide by the the size of the data set (28). This is called the population variance ( σ 2 ). Take the square root of the population variance. This is called the population standard deviation ( σ ). Question (15): How does finding the sample variance and sample standard deviation differ from finding the population variance and population standard deviation you found in question (14)? In your own words, tell why the book says this change was made.
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Data Point Formula for Deviation Deviation from Mean Deviation 2 565 522 598 570 546 338 634 604 482 518 622 392 634 270 537 513 555 412 613 559 519 538 577 611 538 563 551 492 575 621 653 596 Total: σ 2 = σ =
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern