I r i j d dc c dg σ m r f r w t 1 2404 1785 2140 dg

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i R i j D DC C DG Σ = × + × + = M R F R W T 0 (1) 2404 1785 2140 DG × = + R W i j k 6 6 z y DC C C C F F × = + R F j k Substituting and solving Eq. (1) gives 2404 lbf in = T i 297.5 lbf z C F = − 365.7 lbf y C F = − D C Σ = + + = F F F W 0
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