3.15 * 10
7
N/m
2
= 9.8 N / 3.019 * 10
-7
m
2
6.49 * 10
7
N/m
2
= 19.6 N / 3.019 * 10
-7
m
2
9.73 * 10
7
N/m
2
= 29.4 N / 3.019 * 10
-7
m
2
1.29 * 10
8
N/m
2
= 39.4 N / 3.019 * 10
-7
m
2
1.62 * 10
8
N/m
2
= 49 N / 3.019 * 10
-7
m
2
1.94 * 10
8
N/m
2
= 58.8 N / 3.019 * 10
-7
m
2
2.27 * 10
8
N/m
2
= 68.6 N / 3.019 * 10
-7
m
2
Strain
L/L
1.03 * 10
-3
= 0.71 mm / 690 mm
8.12 * 10
-4
= 0.56 mm / 690 mm
6.81 * 10
-4
= 0.47 mm / 690 mm
5.22 * 10
-4
= 0.36 mm / 690 mm
3.62 * 10
-4
= 0.25 mm / 690 mm
1.88 *10
-4
= 0.13 mm / 690 mm
0.00= 0.00 mm / 690 mm
L = L
2
– L
0
0.71= 17.49 mm – 16.78 mm
0.56= 17.34 mm – 16.78 mm
0.47= 17.25 mm – 16.78 mm
0.36= 17.14 mm – 16.78 mm
0.25= 17.03 mm – 16.78 mm
0.13= 16.91 mm – 16.78 mm
0.00= 16.78 mm – 16.78 mm
Applied Force
F = mg
= (2kg)(9.8 m/s
2
)
= 19.6 N
(Continue for each
weight)

2)
The data points in both my graphs fall in a very straight line that when adding the
tool of straight lines in Excel, it is almost impossible to notice. In graph I, the line is
increasing, making the slope positive. In graph II it is inversely opposite making the
slope similar and negative. The factors that would cause a deviation from a straight
line is human error, incorrectly adjusting the micrometer with bubble, inaccuracy of
the micrometer, inaccuracy with measurements regarding precision and accuracy
and incorrect calculations. These are all possibilities that can make the laboratory go
wrong.
3)
If the wire in our apparatus was replaced with one that is twice as thick,
L
would
increase more slowly because it would take longer for elongation to occur on the
same level as with a thinner wire. Force would not change as the mass of the weights
would still remain constant. If the wire was thicker, the diameter would also double
therefore the stress would be altered(decrease twice as much). Strain would also
change as discussed previously because of
L.
The value of Young’s Modulus would
decrease twice as much. The only aspect to remain constant is force and the rest
would simply decrease by twice the amount.

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- Spring '16
- Force, applied force