15 10 7 Nm 2 98 N 3019 10 7 m 2 649 10 7 Nm 2 196 N 3019 10 7 m 2 973 10 7 Nm 2

15 10 7 nm 2 98 n 3019 10 7 m 2 649 10 7 nm 2 196 n

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3.15 * 10 7 N/m 2 = 9.8 N / 3.019 * 10 -7 m 2 6.49 * 10 7 N/m 2 = 19.6 N / 3.019 * 10 -7 m 2 9.73 * 10 7 N/m 2 = 29.4 N / 3.019 * 10 -7 m 2 1.29 * 10 8 N/m 2 = 39.4 N / 3.019 * 10 -7 m 2 1.62 * 10 8 N/m 2 = 49 N / 3.019 * 10 -7 m 2 1.94 * 10 8 N/m 2 = 58.8 N / 3.019 * 10 -7 m 2 2.27 * 10 8 N/m 2 = 68.6 N / 3.019 * 10 -7 m 2 Strain L/L 1.03 * 10 -3 = 0.71 mm / 690 mm 8.12 * 10 -4 = 0.56 mm / 690 mm 6.81 * 10 -4 = 0.47 mm / 690 mm 5.22 * 10 -4 = 0.36 mm / 690 mm 3.62 * 10 -4 = 0.25 mm / 690 mm 1.88 *10 -4 = 0.13 mm / 690 mm 0.00= 0.00 mm / 690 mm L = L 2 – L 0 0.71= 17.49 mm – 16.78 mm 0.56= 17.34 mm – 16.78 mm 0.47= 17.25 mm – 16.78 mm 0.36= 17.14 mm – 16.78 mm 0.25= 17.03 mm – 16.78 mm 0.13= 16.91 mm – 16.78 mm 0.00= 16.78 mm – 16.78 mm Applied Force F = mg = (2kg)(9.8 m/s 2 ) = 19.6 N (Continue for each weight)
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2) The data points in both my graphs fall in a very straight line that when adding the tool of straight lines in Excel, it is almost impossible to notice. In graph I, the line is increasing, making the slope positive. In graph II it is inversely opposite making the slope similar and negative. The factors that would cause a deviation from a straight line is human error, incorrectly adjusting the micrometer with bubble, inaccuracy of the micrometer, inaccuracy with measurements regarding precision and accuracy and incorrect calculations. These are all possibilities that can make the laboratory go wrong. 3) If the wire in our apparatus was replaced with one that is twice as thick, L would increase more slowly because it would take longer for elongation to occur on the same level as with a thinner wire. Force would not change as the mass of the weights would still remain constant. If the wire was thicker, the diameter would also double therefore the stress would be altered(decrease twice as much). Strain would also change as discussed previously because of L. The value of Young’s Modulus would decrease twice as much. The only aspect to remain constant is force and the rest would simply decrease by twice the amount.
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  • Spring '16
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