# Response see section 112 the completely randomized

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Response: See section 11.2 The Completely Randomized Design (One-Way ANOVA)Difficulty: Medium
27.Cindy Ho, VP of Finance at Discrete Components, Inc. (DCI), theorizes that the discountlevel offered to credit customers affects the average collection period on credit sales.Accordingly, she has designed an experiment to test her theory using four sales discount rates(0%, 2%, 4%, and 6%) by randomly assigning five customers to each sales discount rate. Cindy'sexperimental design is a ________.Response: See section 11.5 A Factorial Design (Two-Way ANOVA)
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Difficulty: Medium28.Cindy Ho, VP of Finance at Discrete Components, Inc. (DCI), theorizes that the discountlevel offered to credit customers affects the average collection period on credit sales.Accordingly, she has designed an experiment to test her theory using four sales discount rates(0%, 2%, 4%, and 6%) by randomly assigning five customers to each sales discount rate. InCindy's experiment, "average collection period" is ________.Response: See section 11.4 The Randomized Block Design
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Difficulty: Easy29.Cindy Ho, VP of Finance at Discrete Components, Inc. (DCI), theorizes that the discountlevel offered to credit customers affects the average collection period on credit sales.Accordingly, she has designed an experiment to test her theory using four sales discount rates(0%, 2%, 4%, and 6%) by randomly assigning five customers to each sales discount rate. InCindy's experiment, "sales discount rate" is ______.
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e) a constantAns: bResponse: See section 11.4 The Randomized Block DesignDifficulty: Medium30.Cindy Ho, VP of Finance at Discrete Components, Inc. (DCI), theorizes that the discountlevel offered to credit customers affects the average collection period on credit sales.Accordingly, she has designed an experiment to test her theory using four sales discount rates(0%, 2%, 4%, and 6%) by randomly assigning five customers to each sales discount rate. Cindy'snull hypothesis is ______.a)μ1=μ2=μ3=μ4=μb)μ1μ2μ3μ4μc)μ1μ2μ3μd)μ1=μ2=μ3=μe)μ1μ2=μ3=μAns: d55444

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