Exam3 - review questions KEY

# Da y openin g il openin g ip recei pt ord er wit h

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Da y Openin g I.L. Openin g I.P. Recei pt Ord er Wit h- dra w Closin g I.L. Closin g I.P. 1 240 610 0 190 50 420 2 50 420 370 135 285 285 3 285 285 0 495 140 145 640 4 145 640 0 150 -5 490 5 -5 490 495 150 340 340 6 340 340 0 440 140 200 640 7 200 640 0 140 60 500 Tot al 865 935 104 5 Q 3 P system - Suppose the OUL = 780, order interval (OI) is 3 days and the lead-time ( LT ) is 2 days. Opening on hand inventory day 1 is 240. An order of 370 units is expected to arrive on day 2. Withdrawals during the next 7 days are shown in the table. Complete all calculations in the table and verify the formula below for X = 1 and Y= 6: Closing IP (day Y) = Opening IP (day X) + Orders from X to Y – Withdrawals from X to Y. 640 = 610 + 935 - 905
Level P1 P2 P3 P4 Capacity 5200 5200 5200 5200 Demand 4500 5650 5400 5450 Basic Plan 5000 5000 5000 5000 Inventor y 1000 1500 650 450 0 Adjust. 1 4700 5100 5100 5100 Inventor y 1000 1200 650 350 0 Q4 Prepare aggregate plan using level strategy and the following constraints: ( 1) Do not exceed capacities. (2) Inventories cannot exceed 1200. (3) No shortages permitted. Explain how you obtained the basic plan and explain adjustments. Initial inventory is 1000. Avg. demand (with initial inventory of 1000) = [(4700 + 5650 + 5400 + 5450) – 1000]/4 = 5000. Use this value in the basic plan. Basic Plan: Inventory exceeds 1200 in P1. Adjustment 1: move 300 units from P1 to P2, P3 and P4 equally (100 units each). Plan feasible!

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Q5 In the beer distribution game, (number of) kegs at various stages at the beginning on day 15 are shown below. Extreme right box for each party is the warehouse. Smaller boxes to the left are stages. Numbers next to the party names, in parenthesis, indicate the backlog quantities copied from their customer’s form.
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