D n d rata rata beda n banyaknya dana s d standart

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_ d n _ d = rata-rata beda n = banyaknya dana S d = standart deviasi dari beda (∑ d ) 2 d 2 n n – 1 S d = 135 2 2575 – 12 12 – 1 S d = = 9,799 11,25 9,799 12 t hitung = t tabel α=0,05 db=11 = 1,796 db = n – 1 = 12 – 1 = 11 t hitung > t tabel α=0,005 db = 11 H0 ditolak, H1 diterima, dengan kesimpulan pelatihan meningkatkan jumlah penjualan.
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UJI t RATA-RATA TIDAK BERPASANGAN HIPOTESIS : Rata-rata penjualan perusahaan A lebih tinggi dari perusahaan B. H0 : Rata-rata penjualan perusahaan A tidak lebih tinggi dari perusahaan B. H1 : Rata-rata penjualan perusahaan A lebih tinggi dari perusahaan B. H0 : ditolak jika t hitung t tabel α = 0,05 NO. X 1 X 1 2 X 2 X 2 2 1 260 67600 230 52900 2 245 60025 200 40000 3 300 9000 230 52900 4 230 52900 240 57600 5 225 50625 220 48400 6 275 75625 240 57600 7 400 160000 245 60025 8 250 62500 250 62500 9 275 75625 260 67600 10 280 78400 275 75625 11 290 84100 300 90000 12 300 90000 275 75625 Rata 277.5 247.08 JML 3330 947400 2965 740775 X 1 = Penjualan perusahaan A X 2 = Penjualan perusahaan A
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. _ _ X 1 - X 2 { (n 1 – 1)s 1 2 + (n 2 – 1)s 2 2 } { 1 1 } n 1 + n 2 - 2 n 1 n 2 + t hitung = n ( X 1 )2 i=1 n ∑ X 1 2 i=1 n n – 1 s 1 = 3330 2 12 947400 – 12 – 1 S 1 = = 46,048 2965 2 740775 – 12 12 – 1 S 2 = = 27,258
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. 277,5 – 247,08 (12 – 1) x 46,048 + ( 12 – 1) x 27,258 { }{ 1 1 } + 12 + 12 – 2 12 12 = 12,308 t hitung = t tabel α = 0,05 db = 11 = 1,812 db = n – 2 = 12 – 2 = 10 t hitung > t tabel α = 0,05 db = 11 H0 ditolak, H1 diterima, dengan kesimpulan rata-rata penjualan perusahaan A lebih dari perusahaan B
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ANALISIS VARIANS DATA BERPASANGAN HIPOTESIS: Semakin banyak pelatihan maka tingkat penjualan semakin meningkat H0 : Banyaknya pelatihan tidak meningkatkan penjualan H1 : Banyaknya pelatihan meningkatkan penjualan H0 ditolak jika F hitung F tabel = 0,05 NO X 1 X 1 2 X 2 X 2 2 X 3 X 3 2 X total X 2 total 1 2 4 3 9 5 25 10 38 2 4 16 5 25 8 64 17 105 3 3 9 4 16 7 49 14 74 4 2 4 5 25 8 64 15 93 5 1 1 3 9 5 25 9 35 6 3 9 4 16 6 36 13 61 7 2 4 5 25 7 49 14 78 8 1 1 6 36 9 81 16 118 9 3 9 3 9 4 16 10 34 10 2 4 4 16 6 36 12 56 JML 23 61 42 186 65 445 130 692 X 1 = Jumlah produk terjual per hari sesudah pelatihan 1 X 2 = Jumlah produk terjual per hari sesudah pelatihan 2 X 3 = Jumlah produk terjual per hari sesudah pelatihan 3
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(∑ X total ) 2 JK total = X 2 total N total JK total = Jumlah Kuadrat Total JK total = 692 – 130 2 30 = 128,6667 (∑ X 1 ) 2 (∑ X 2 ) 2 (∑ X 3 ) 2 (∑ X total ) 2 JK ant = + + + n 1 n 2 n 3 n total JK ant = Jumlah Kuadrat Antara Kelompok JK ant = 23 2 42 2 65 2 130 2 + + 10 10 10 30 = 88,4667 JK dal = JK total JK ant JK dal = Jumlah Kuadrat Antara Kelompok JK dal = 128,6667 – 88,4667 = 40,2
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. db total = N – 1 db total = Derajat bebas total db total = 30 – 1 = 29 db ant = K – 1 K = Banyaknya variabel db ant = 3 – 1 = 2 db dal = N – K – 1 db dal = 30 – 3 – 1 = 26 MK ant = JK ant 88,4667 db ant + 2 = 44,2334 MK ant = Median Kuadrat Antara
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. MK dal = JK dal db dal 40,2 = 26 H0, ditolak dan H1 diterima dengan kesimpulan banyaknya pelatihan akan meningkatkan kemampuan menjual = 1,5462 MK dal = Median kuadrat dalam kelompok F hitung = MK ant MK dal = 44,2334 1,5462 = 28,6087 F tabel α = 0,05 = 3,37 F hitung > F tabel α=0,05 TABEL ANALISIS VARIANS Jumlah Kuadrat Derajat Bebas Median Kuadrat F hitung F 0,05 Antar Kelompok 88.4667 2 44.2334 28.6087 3.37 Dalam Kelompok 40.2 26 1.5462 Total 128.6667 29
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TABEL F V 2 = d b Penyebut V 1 = db Pembilang 1 2 3 4 5 1 2 3 4 5 6 7 8 9 10 11 12 13 14 3,37
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ANALISIS VARIANS DATA TIDAK BERPASANGAN HIPOTESIS: Terdapat perbedaan kemamuan menjual produk terjual
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