Practice Exam II Solution.pdf

1 20 1 3 2 4 1 2 1 5 3 4 1 4 if 1 13 therefore 2 65 1

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? = ? = 1 20 = ? 1 ? 3 ? 2 ? 4 ? 1 ? 2 = 1 5 , ? 3 ? 4 = 1 4 If ? 1 = 13 Therefore ? 2 = 65 ? 1 ? 2 ? 3 ? 4 Bearing A Bearing B
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