lec_4_cond_13

# The a locus with alleles a1 and a2 defnitions p

This preview shows pages 3–6. Sign up to view the full content.

The A-locus with alleles A1 and A2 DeFnitions: P = proportion of the A1A1 genotype H = proportion of the A1A2 genotype Q = proportion of the A2A2 genotype Zygote Pool Syngamy Survival Gametogenesis Mapping Zygote pool to Adult pool Mapping Adult pool to Gamete pool (or gene pool) p = Prop.(A1 allele) = {2(PN) + 1(HN)}/2N = P + H/2 q = Prop.(A2 allele) = {2(QN) + 1(HN)}/2N = Q + H/2 Haploid Gamete Pool Diploid Adult Pool p = P + H/2 P A1A1 Q A2A2 H A1A2 q = Q + H/2 p A1 q A2 SUMMARY Mapping Gamete pool to Zygote pool 16 (with respect to most alleles in genotype) Adult Pool Gamete Pool Zygote Pool Syngamy Survival Gametogenesis Haploid Gamete Pool Diploid Zygote Pool p A1 q A2 P A1A1 Q A2A2 H A1A2 ? H A1A2 Zygote Pool P A1A1 Q A2A2 H A1A2 Adult Pool NO CHANGE since no evolutionary forces are operating Q A2A2 P A1A1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Probability of 2 independent events (A & B) is the product of the probability of each Start with a simple result from probability theory: Probability of A and B = PROB(A) X PROB(B) Example: To make this mapping we need to systematically consider all possible matings in the population It is not important that you calculate every entry in the table -- but that you understand how the table was created and what it represents Random mating table Mating ˁ ˂ PROB. Offspring (Zygotes) A1A1 A1A2 A2A2 A1A1 A1A1 P 2 P 2 A1A1 A1A2 P x H PH / 2 PH / 2 A1A1 A2A2 Q 2 Q 2 A1A2 A1A1 A1A2 A1A2 A1A2 A2A2 H x P HP / 2 HP / 2 H 2 H 2 / 2 H 2 / 4 H 2 / 4 H x Q HQ / 2 HQ / 2 A2A2 A2A2 A2A2 A1A1 A1A2 A2A2 Q x P QP Q x H QH / 2 QH / 2 P x Q PQ Σ = 1.0 Σ = p 2 Σ = 2 p q Σ = q 2 Proportion of all offspring that are A2A2 Proportion of all offspring that are A1A2 Proportion of all offspring that are A1A1 17 Diploid Zygote or Adult Pool p = (P + H / 2) Haploid Gamete Pool p A1 q A2 P A1A1 Q A2A2 H A1A2 p 2 2 p q q 2 q = (Q + H / 2) (Quantitative solution) --because there is no selection Adult pool = Zygote pool Haploid Gamete Pool p A1 q A2 Diploid Zygote Pool P A1A1 Q A2A2 H A1A2 P = p 2 Q = q 2 H = 2 p q Putting all the pieces together We can summarize our table of all possible matings to map the transition from gene pool to zygote pool
Called the Binomial Square Principle since Lack of change in gene and genotype frequencies called HARDY-WEINBERG EQUILIBRIUM IF random mating & no evolutionary forces are operating THEN P, H, Q, p P = p 2 H = 2 p q Q = q

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page3 / 6

The A locus with alleles A1 and A2 DeFnitions P proportion...

This preview shows document pages 3 - 6. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online