The sample data could definitely happen by random

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The sample data could definitely happen by random chance. It had an 84% chance of happening. We fail to reject H0. There is not significant sample evidence to reject the claim that 25% of drowning deaths happen at the beach. 13. P1 : percent of high level preforming people that drink Gatoraid. P2 : percent of high level preforming people that drink water. 0 1 2 1 2 : (gatoraide is not better than water) : (gatoraide is better than water) A H p p H p p Type I: Reject H0 by mistake and support that people perform better when drinking Gatoraide when they reall don’t. This would result in people drinking Gatoraid thinking it will improve performance when it really does not. Gatoraid may be liable for false advertising since they said they have significant data when they really do not have evidence. To decrease the chances of making a type I error, we could lower the significance level. Type II: Fail to Reject H0 by mistake and tell people that those that drink Gatoraid perform no better than those that drink water, when they really do. People may not buy Gatoraid since they do not think it works. Gatoraid may lose money in sales. To decrease the chances of making a type II error, we should increase the sample size.
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14. 0 : 2% (Put out recall) : 2% (Will not put out recall) A H p H p Type I: Reject H0 by mistake and support that the bracket is defective less than 2% of the time when it is actually defective much more. The car company will not put out a recall when they should. If a tire falls off the truck on the road it may cause an accident and injuries. The company would be liable for damages and may be sued. Type II: Fail to Reject H0 by mistake, so we will tell the company to put out a general recall when they really don’t need to. This will cost the company money to replace brackets that are probably not defective. The company may also lose some reputation with its customers. Hypothesis Test Act 13 answers 1. 0: 1 2 3 :at least one is not equal H p p p HA Expected values are n/k = 60/3=20. Notice all expected values >5. The data was randomly collected also. So it does meet the assumptions necessary for a goodness of fit test. Our test statistic was Chi squared = 11.7. Our P-value was 0.0029. Since our p-value was less than our sig level of 0.05 we reject the null hypothesis. There is significant sample evidence to reject the claim that the percent of people from each political part are the same. 2. H0: p1=.43 , p2=.23 , p3=0.2 , p4 = 0.08 , p5 = 0.06 HA: Distribution is different than the null hypothesis (at least one is not equal) (claim) The data was randomly selected and all the expected values from Statcato were greater than 5. The test statistic was chi squared = 17.3766 and the p-value was 0.0016. We reject the null hypothesis since pvalue is less than sig level 0.05. There is sufficient sample evidence to support the claim that the percentages of COC students is different than what was given in the magazine.
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