?
1.
∞
summationdisplay
n
=0
c
n
(

8)
n
is divergent
2.
∞
summationdisplay
n
=0
c
n
(

6)
n
is convergent
3.
∞
summationdisplay
n
=0
c
n
(

8)
n
is convergent
4.
∞
summationdisplay
n
=0
c
n
(

6)
n
is divergent
014
10.0 points
Find the interval of convergence of the
power series
∞
summationdisplay
n
=1
2
x
n
√
n
.
1.
interval of cgce = [

2
,
2)
2.
interval of cgce = (

2
,
2)
3.
interval of cgce = [

2
, ,
2]
4.
interval of cgce = [

1
,
1]
5.
interval of cgce = (

1
,
1)
6.
interval of cgce = (

1
,
1]
7.
interval of cgce = (

2
,
2]
8.
interval of cgce = [

1
,
1)
015
10.0 points
Determine the interval of convergence of
the series
∞
summationdisplay
n
=1
(

1)
n
2
n
(
n
+ 3)
x
n
.
1.
converges only at
x
= 0
2.
none of the other answers
3.
interval convergence = (

2
,
2]
4.
interval convergence =
parenleftBig

1
2
,
1
2
bracketrightBig
5.
interval convergence =
bracketleftBig

1
3
,
1
3
parenrightBig
6.
interval convergence = (
∞
,
∞
)
7.
interval convergence = [

3
,
3)
016
(part 1 of 2) 10.0 points
For the series
∞
summationdisplay
n
=1
x
n
(
n
+ 4)!
,
(i) determine its radius of convergence,
R
.
1.
R
=
∞
2.
R
= 0
3.
R
= 1
4.
R
= 4
5.
R
=
1
4
017
(part 2 of 2) 10.0 points
husain (aih243) – HW 3 – mann – (54675)
4
(ii) Determine the interval of convergence
of the series.
1.
interval convergence = (

4
,
4)
2.
interval convergence = [

4
,
4]
3.
interval convergence = [

1
,
1]
4.
converges only at
x
= 0
5.
interval convergence = (

1
,
1]
6.
interval convergence = (
∞
,
∞
)
018
10.0 points
Find the interval of convergence of the
power series
∞
summationdisplay
n
=0
5
n
3
n
5
+ 7
x
n
.
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 Fall '07
 Sadler
 Mathematical Series, Radius of convergence, interval convergence, 1 3k