2131 o 2131 o 1600 1332 smallest of the set 1332 is

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21.31% O 21.31% O ÷ 16.00 = 1.332 (smallest of the set)1.332 is the smallest of this set of numbers, so it is divided into each of the set ofnumbersC = 5.993 ÷ 1.332 = 4.5H = 6.657 ÷ 1.332 = 5O = 1.332 ÷ 1.332 = 1Since C is 4.5, multiply all numbers by 2 to get:C9H10O2Question 50 / 0 ptsNumber your answers, and be sure to show your work.BALANCE THE FOLLOWING EQUATIONS:1. SrBr2+ (NH4)2CO3→ SrCO3+ NH4Br2. FeS2+ O2→ Fe2O3+ SO2
2) Fes+O2 Fe2O3+ 2SO21. SrBr2+ (NH4)2CO3→ SrCO3+ 2 NH4Br2. 4 FeS2+ 11 O2→ 2 Fe2O3+ 8 SO2Question 60 / 0 ptsDetermine which of the following double replacement reactions will occur using thesolubility rules and complete the equations that do:1. Ca+2, Cl2-1+ Al+3, 3 NO3-12. Pb+2, 2 NO3-1+ 2 Na+1, 2 Br-1
Question 70 / 0 ptsDetermine which of the following single replacement reactions will occur using theactivity series and complete the equations that do:
1. Cl2+ 2 F-12. Ba + Fe+2Label each of the following reactions as either (1) Combination, (2) Decomposition, (3)Combustion, (4) Double Replacement or (5) Single Replacement and then balance theequation.3. C6H12O6+ O2→ CO2+ H2O4. HCl + NaOH → NaCl + H2O5. Al + Fe(NO3)3→ Fe + Al(NO3)36. S + O2→ SO37. H2SO4→ SO3+ H2OYour Answer:1) it can not occur2) Br2+ 2 I-1→ I2+ 2 Br3) combustion4) Double replacement5) single replacement6) combustion7) decomposition1. Cl2+ 2 F-1→ Will not occur since F2is more active than Cl22. Ba + Fe+2→ Fe + Ba+2Will occur since Ba is more active than Fe3. C6H12O6+ 6 O2→ 6 CO2+ 6 H2OCombustion4. HCl + NaOH → NaCl + H2ODouble Replacement5. Al + Fe(NO3)3→ Fe + Al(NO3)3Single Replacement
6. 2 S + 3 O2→ 2 SO3Combination7. H2SO4→ SO3+ H2ODecompositionQuestion 80 / 0 ptsShow the calculation of the oxidation number (charge) of ONLY the atoms which are

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