In a random sample of 550 current sales, 188 came from Clothing, 153 Home Appliances,
83 Housewares, 54 Cosmetics, 61 Jewelry, and 11 Other. At α=0.10, can the manager conclude
that the distribution of sales among the departments has changed?
A.
yes because the p-value is .0006
B.
no, because the p-value is .0006
C.
yes because the p-value = .0321

D.
no, because the p-value = .0321
Answer Key: C
Feedback:
Clothing
Home App. Housewares
Cosmetics
Jewelry
Other
Observed
Counts
188
153
83
54
61
11
Expected
Counts
550*.30 =
165
550*.25 =
137.5
550*.18 = 99
550*.13 =
71.5
550*.12 =
66
550*.02=
11
Use Excel to find the p-value
=CHISQ.TEST(Highlight Observed, Highlight Expected)
The p-value is < .10, Reject Ho. Yes, this is significant.
Part 2 of 4 - Chi Square Test for Independence
6.0/ 6.0 Points
Question 9 of 20
1.0/ 1.0 Points
Click to see additional instructions
A restaurant chain that has 3 locations in Portland is trying to determine which of their 3
locations they should keep open on New Year’s Eve. They survey a random sample of
customers at each location and ask each whether or not they plan on going out to eat on New
Year’s Eve. The results are below. Run a test for independence to decide if the proportion of
customers that will go out to eat on New Year’s Eve is dependent on location. Use
α=0.05
NW Location
NE Location
SE Location
Will Go Out
66
40
45
Won’t Go Out
20
25
20
.

Enter the
P
-Value - round to 4 decimal places. Make sure you put a 0 in front of the decimal.

Question 10 of 20
1.0/ 1.0 Points
A manufacturing company knows that their machines produce parts that are defective on
occasion. They have 4 machines producing parts, and want to test if defective parts are
dependent on the machine that produced it. They take a random sample of 321 parts and find
the following results. Test at the 0.05 level of significance.

Machine 1
Machine 2
Machine 3
Machine 4
Defective
10
15
16
9
Non-Defective
72
75
66
58
Can it be concluded that number of defective parts is dependent on machine?