neighbors as the adjacency list of s in G 8 For each t list ofneighbors 9If not

# Neighbors as the adjacency list of s in g 8 for each

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neighbors as the adjacency list of s in G 8. For each t list of neighbors: 9. If not visited( t ): 10. ExploreSystem( t , G ) GenerateInducedGraph( G 0 , dir ) 1. G := G 0 2. For each vertex v G : 3. if (isRed( v , dir ) == false ): 4. remove v from G by removing its adjacency list 5. For each edge ( u , v ) G : 6. if (isRed( v , dir ) == false ): 7. remove edge ( u , v ) from G 8. Return G HasInfiniteRedLoops( s 0 ) 1. G = GenerateGraph( s 0 ) 2. For i : = 1 , 2 , 3 , 4: 3. G i := GenerateInducedGraph( G , dir i ): 4. if (hasCycle( G i ) == true ): 5. Return true 6. Return false Proof of correctness. The procedures GenerateGraph() and ExploreSystem() correctly generate an adja- cency list of G since essentially they perform a DFS in G and in line 7 of procedure ExploreSystem() we add in G the adjacency list of the vertex we visit and then we recursively explore this adjacency list. Also, the procedure GenerateInducedGraph() generates correctly an induced graph G i since it removes from G all the vertices (states) that have green light in direction d i and all of their incoming edges. The only thing that remains to be proved (and also it implies the correctness of the procedure HasIn- finiteLoops()) is that a car can wait infinitely in a direction dir i if and only if there is a cycle in the induced subgraph G i . Let’s prove first the direction: a car can wait infinitely in a direction dir i there is a cycle in the induced subgraph G i . Well, if a car can wait infinitely in a direction dir i then it means that there is a cycle in G where all of its vertices (or equivalently states) have red light in that direction dir i . However, by construction of the inducted graph G i we don’t remove any vertices from the original graph G that have red light in that direction dir i neither we remove any edges of G that go to such vertices. Thus, the same cycle of G should be also found in G i . The other direction: there is a cycle in the induced subgraph G i a car can wait infinitely in a direction dir i . This follows from the fact that the vertices and the edges of the induced subgraph G i can be also CS 170, Fall 2014, Sol 4 12