# 9 record the time 3 times for m 2 7g 12g 17g 22g and

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9. Record the time 3 times for m 2 =7g, 12g, 17g, 22g, and 27g by using the short silver mass (5g) and the tall silver mass.
Lab Data m 2 t 1 (s) t 2 (s) t 3 (s) t avg (s) A=2d/t 2 (m/s 2 ) F=m 2 *(g-A) (N) 1 0.007 1.7810 1.7837 1.7958 1.7868 0.376 0.066 2 0.012 1.4694 1.3920 1.4036 1.4217 0.594 0.111 3 0.017 1.1522 1.1536 1.1509 1.1522 0.904 0.151 4 0.022 1.0211 1.0147 1.0129 1.0162 1.162 0.190 5 0.027 0.9256 0.9337 0.9316 0.9303 1.386 0.227 Computations and Graphs t avg = t 1 + t 2 + t 3 3 a = 2 d t avg 2 F = m 2 *(9.8– a) Percent Difference = 0.191 S lop e 0.191 × 100% = 0.191 0.1547 0.191 × 100% = 19% 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 0 0.05 0.1 0.15 0.2 0.25 F vs A A=2d/t2 (m/s2) F=m2*(g-A) (N) F = mA+b m (Slope): 0.1547 N/m/s 2
b (Y-intercept): 0.01210 N Correlation: 0.9980 RMSE: 0.004661 N Summary In my case, I could have improved on the measurements for points #2, since these data points are not on the best fit line. The percent difference is equal to 19%. It’s low, because my partner and I were accurate in our measurements. The more the slope is closer to 0.191, the smaller the percentage difference. Questions 3. The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. The force acting on the body is equal to the product of the mass of the body on the acceleration reported by this force. This experiment proves the second law of Newton’s 2nd Law of dynamics. We knew the mass of the body, found out the average time for which the body overcomes a certain distance, learned the value of acceleration. And knowing of acceleration and body weight, we easily found out the force.
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